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Ksenya-84 [330]
3 years ago
7

Hello solve it for me 10 points

Mathematics
2 answers:
galben [10]3 years ago
7 0
<span>
I believe the answer is C.
</span>
Monica [59]3 years ago
7 0

Answer:

C.

Step-by-step explanation:

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Anyone knows the answer
murzikaleks [220]

Answer:C

Step-by-step explanation:

3.1 x 10^(-4) x 8.5 x 10^(-2)

3.1 x 8.5 x 10^(-4) x 10^(-2)

26.35 x 10^(-4-2)

26.35 x 10^(-6)

2.635 x 10^1 x 10^(-6)

2.635 x 10^(1-6)

2.635 x 10^(-5)

3 0
3 years ago
H=−4.9t2+25t
lina2011 [118]

ANSWER

5

EXPLANATION

The equation that expresses the approximate height h, in meters, of a ball t seconds after it is launched vertically upward from the ground is

h(t) =  - 4.9 {t}^{2}  + 25t

To find the time when the ball hit the ground,we equate the function to zero.

- 4.9 {t}^{2}  + 25t = 0

Factor to obtain;

t( - 4.9t + 25) = 0

Apply the zero product property to obtain,

t = 0 \: or \:  \:  - 4.9t + 25 = 0

t = 0 \:  \: or \:  \: t =  \frac{ - 25}{ - 4.9}

t=0 or t=5.1 to the nearest tenth.

Therefore the ball hits the ground after approximately 5 seconds.

4 0
3 years ago
Read 2 more answers
HELP ME!!!!! Which choices are equivalent to the fraction below? CHECK ALL THAT APPLY.
slavikrds [6]

Answer:

A and E

Step-by-step explanation:

9^3 / 9^3

Same number on top and bottom so 1 is an answer

look at the exponents, when dividing with exponents, you just subtract them, so it could also be 9^0, which is also 1

3 0
3 years ago
Read 2 more answers
Find three consecutive even integers if three times the first integer is two times<br> the third
lara31 [8.8K]

Solution:

Let's name the three consecutive numbers as y, y + 2, and y + 4.

<u>Note that:</u>

  • => Equation formed: 3(y) = 2(y + 4)

<u>Solve the equation to find the three consecutive numbers.</u>

  • 3(y) = 2(y + 4)
  • => 3y = 2y + 8
  • => 3y - 2y = 8
  • => y = 8

The numbers are 8, 10, and 12.

4 0
2 years ago
Solve the compound inequality 6b &lt; 42 or 4b + 12 &gt; 8. (1 point)
Nitella [24]
6b<42
b<7
4b+12>8
4b>-4
b>-1
b>-1 or b<7
8 0
3 years ago
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