Hi there! The answer is £198.
If you spend 3 / 12 of a certain amount of money, you have 9 / 12 of the money left.
Simplify the fraction.
9 / 12 = 3 / 4.
To find the amount of money left, we multiply this factor by 264. We get the following
£264 × 3/4 = £264 × 0.75 = £198
Therefore the answer is £198
Answer:
Probability of eligible applicants who pass the exam is 0.665
probability of applicants who are ineligible but pass the exam 0.063
Step-by-step explanation:
Total percentage eligible applicants who pass the exam

Total ineligible applicants who pass the exam

All applicants who pass this exam 62.3% + 4.2% = 66.5%
Probability of applicants who pass the exam

Out of 66.5% applicants who pass the exam , 4.2% applicants are ineligible
Probability of applicants who pass the exam is 0.665
probability of applicants who are ineligible but pass the exam 0.063
I honestly don't know, but I think it is 63
Answer:
So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.
270 miles
Step-by-step explanation:
So is A is going faster than B so A will reach the destination first.
When will A reach it's destination?
Let's find out.
To solve this problem, the following will come in handy:
Speed=distance/time or time*Speed=distance or time=distance/speed .
time=distance/speed



So it will take bus A 6 hours to cover the distance of 390 miles.
How much time would have it taken bus B to reach that same distance?


So it would have taken bus B
hours to cover a distance of 390 miles.
So the time difference is
hours.
It will take
more hours than bus A for bus B to complete a distance of 390 miles.
So bus B traveled
miles (used the time*speed=distance) after bus A got to it's destination.
So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.
Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130
