How many times does 3 go into 22
1 answer:
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Check out the attached image for the answers.
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Statement 2 is blank, but it has the reasoning "Corresponding angles postulate"
Because BD || AE, we know that the corresponding angles are congruent.
One pair of corresponding angles is angle 1 and angle 4. This is because they are on the same side of the transversal AC and they are both above their parallel line counter-part. Similarly, angle 2 and angle 3 are another corresponding pair.
So you'll have "angle1=angle4, angle3=angle2" in the first blank slot
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Reason 3 is blank. The statement is that triangle ACE is similar to triangle BCD. The reason why the are similar is the AA (angle angle) similarity postulate. This says that if you know two pairs of angles are congruent, then the triangles are similar. The two pairs of angles were mentioned back on the previous line (line 2)
So you'll put "Angle-Angle Similarity Postulate" in the second blank.
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Look at the line just above the last line. Here we have
1 + (BA/CB) = 1 + (DE/CD)
If we subtract 1 from both sides, we end up with,
BA/CB = DE/CD
which is what will go in the last blank space
Side Note: The last statement will always be what you want to prove. So you can just look at the very top of the problem where it says "Prove:" under the "Given" part. Then just copy/paste the statement you want to prove, which in this case is BA/CB = DE/CD
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Statement 2 is blank, but it has the reasoning "Corresponding angles postulate"
Because BD || AE, we know that the corresponding angles are congruent.
One pair of corresponding angles is angle 1 and angle 4. This is because they are on the same side of the transversal AC and they are both above their parallel line counter-part. Similarly, angle 2 and angle 3 are another corresponding pair.
So you'll have "angle1=angle4, angle3=angle2" in the first blank slot
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Reason 3 is blank. The statement is that triangle ACE is similar to triangle BCD. The reason why the are similar is the AA (angle angle) similarity postulate. This says that if you know two pairs of angles are congruent, then the triangles are similar. The two pairs of angles were mentioned back on the previous line (line 2)
So you'll put "Angle-Angle Similarity Postulate" in the second blank.
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Look at the line just above the last line. Here we have
1 + (BA/CB) = 1 + (DE/CD)
If we subtract 1 from both sides, we end up with,
BA/CB = DE/CD
which is what will go in the last blank space
Side Note: The last statement will always be what you want to prove. So you can just look at the very top of the problem where it says "Prove:" under the "Given" part. Then just copy/paste the statement you want to prove, which in this case is BA/CB = DE/CD
Answer:
1) d) Square
2) Proofs that PWRS is a rhombus are
Length of QS ≠ PR and
Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.
Step-by-step explanation:
The given points (x, y) of the parallelogram are;
E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)
The slope, m, of the segments are found as follows;
By computation, the slope of segment EF = 1.5
The slope of segment FG = -0.67
The slope of segment GH = 1.5
The slope of segment HE = -0.67
Therefore, EF is parallel to GH and FG is parallel to HE
The length of the sides are;
By computation, the length of segment EF = 3.61
The length of segment FG = 3.61
The length of segment GH = 3.61
The length of segment HE = 3.61
The diagonals are;
EG and FH
The length of segment EG = 5.099
The length of segment FH = 5.099
Therefore, the diagonals are equal and the parallelogram is a square
2) The given dimensions are;
P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)
A rhombus has all sides equal
The length of segment PQ = 2.24
The length of segment QR = 2.24
The length of segment RS = 2.24
The length of segment PS = 2.24
The diagonals are;
QS and PR
The length of segment QS = 4.24
The length of segment PR = 1.41
The slope of segment QR = -0.5
The slope of segment PS = -0.5
The slope of segment RS = -2
The slope of segment QP = -2
Therefore, QS≠QR the parallelogram is a rhombus
The correct option ;
Length of QS ≠ PR and
Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.
Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2
<span>The function which has a constant halving time is in the following form
</span>
Where: A₀ is the <span>initial amount
h is the half life time or the halving time.
</span><span> t is the time
</span> A(t) <span>the amount<span> that remains at time t
</span></span>
The previous function represents an Exponential decay<span> function.
</span>
so, The correct answer is option B. <span>Exponential decay</span>
</span>
Where: A₀ is the <span>initial amount
h is the half life time or the halving time.
</span><span> t is the time
</span> A(t) <span>the amount<span> that remains at time t
</span></span>
The previous function represents an Exponential decay<span> function.
</span>
so, The correct answer is option B. <span>Exponential decay</span>