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4 years ago

Match the mean, median, mode, and range for the data set below. 19, 18, 16, 6, 8, 18, 14, 14, 13

Mathematics

2 answers:

Shalnov [3]4 years ago

8 0

Answer: the mean is 13.4

Step-by-step explanation:

GaryK [48]4 years ago

3 0

Answer:

hello :) mean is 14, median is 14, mode is 14 and 18, range is 13

Step-by-step explanation:

for mean add all numbers and divide by how many numbers there are, for median put the numbers in order then find the middle one, for mode find the number(s) that appear the most, and for range subtract the smallest number from the biggest.

hope this helps and im sorry if im wrong but i tried :)

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Am I correct if not help plzzz

11Alexandr11 [23.1K]

Hey there!

You got the first part right where you added r to both sides. However, you need to make sure that you complete all actions on both sides, including canceling out parts of terms by division. The only thing you need to do is divide both sides by h instead of just the left. This will make your answer:

$y = \frac{b+r}{h}$

Hope this helped you out! :-)

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3 years ago

The graphs below have the same shape. What is the equation of the blue graph?

scoundrel [369]

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3 years ago

Which fractions are equivalent to 40

pickupchik [31]

Answer:

80/2, 120/3, 160/4, 200/5, 240/6, 280/7, 320/8, 360/9, 400/10, 440/11, 480/12, 520/13, 560/14 , 600/15, 640/16, 680/17, 720/18, 760/19, 800/20, 840/21

Step-by-step explanation:

3 0

3 years ago

47% of the company's monthly income is used to pay the owner's personal salary. If the amount of the owner's salary is $2176.10,

Setler [38]

You have to set up a ratio between the owner's income and the total income so

47 = 2176.10
53 x

then cross multiply to slove for x

47x = 115333.30

then divide each side by 47

x = 2453.90

the company makes $ 2453.90

5 0

3 years ago

Please help me tysm if you do

Whitepunk [10]

Answer:

R=155°

S=25°

T=155°

Step-by-step explanation:

R + 25° =180°

R = 180° - 25°

R = 155°

(2) S + 155° =180°

S = 180° - 155°

S = 25°

T = R because t is opposite of r

I hope this was helpful

4 0

3 years ago