Answer (least to greatest):
- -2.4
- -2.25
- -11/5
- 15/10
- 1.6
I hope this helps!
A rectangular school banner
has a length of 44 inches, a perimeter of 156 inches, and an area of 1,496
square inches. the cheerleaders make signs similar to the banner. the length of
a sign is 11 inches. First solve the width of the rectangle:
1496 sq in/ 44 = 34 in
So the sign has also a width
of 34 in and a length of 11 so the area is 34*11 =374 sq in
<span>The perimeter is (34*2)
+(11*2) =90 in</span>
Hello,
Let's assume top left corner: A
top right corner : B
Bottom right corner: C
Bottom left corner :D
M= middle of [CD]
ABM is a triangle rectangular isocel:
(3√2)²+(3√2)²=y²
==>y²=2*9*2
==>y²=36
==>y=6
The triangle BCM is rectangular with MB=3√2, MC=y/2=3
x²+3²=(3√2)²
==>x²=9*2-9
==>x²=9
==>x=3
Answer:
k = -1/240
Step-by-step explanation:
to evaluate the value of k in the expression 1/3k+80=1/2k+120
we have
1/3k+80=1/2k+120
collect the like terms for easy evaluation
1/3k - 1/2k = 120 -80
1/3k - 1/2k = 40
find the lcm
2 - 3/6k = 40
-1/ 6k = 40
cross multiply
6k x 40 = -1
240k = -1
divide both sides by 240
240k/240 = -1/ 240
k = -1/240
therefore the value of k in the expression 1/3k+80=1/2k+120 is equals to -1/240
Answer:
D not here
Step-by-step explanation:
A-2 is not reasonable as it is not possible
C- bot possible
B- maybe
D- most reasonable