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REY [17]
3 years ago
7

A local fair has an entrance fee of $10. Each ride costs $1.25.

Mathematics
1 answer:
Archy [21]3 years ago
6 0

Answer:

Step-by-step explanation:

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Multiplicitave inverse of 3/5
barxatty [35]

Multiplicative inverse is a number with which if you multiply you get 1.

Hence 5/3 is the multiplicative inverse of 3/5

Since 3/5×5/3=1

8 0
3 years ago
Find a and b if the points p(6,0) and q(3,2) lie on the graph of ax + by =12
s2008m [1.1K]

Answer:

a= 2

b = 3

Step-by-step explanation:

Given

p(x,y) = (6,0)

q(x,y) = (3,2)

ax + by = 12

Required

Find a and b

In p(x,y) = (6,0), x = 6 and y = 0.

This gives:

a*6 + b*0 = 12

6a = 12

Divide by 6

a= 2

In q(x,y) = (3,2). x = 3 and y = 2.

This gives:

a*3 + b*2 = 12

3a + 2b = 12

Substitute 2 for a

3*2 + 2b = 12

6 + 2b = 12

Collect Like Terms

2b = 12 - 6

2b = 6

Divide by 2

b = 3

7 0
3 years ago
% of 50 = 12.5<br> Please help.
andrezito [222]

Answer:

25 percent

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Kylie is planning to provide online science and Chinese language tutoring sessions. The sciences
Ivahew [28]

Answer:

120 ≤ 20c + 40s

Step-by-step explanation:

(Assuming her name is Kylie, who is giving 40 minute science sessions and 20 minute Chinese sessions.)

The unit for time will be minutes.

Write an equation for time needed for science sessions

40s = t

Write an equation for time needed for Chinese sessions

20c = t

Combine the two equations for the total time.

20c + 40s = total time

She does not want the total time to be more than two hours.

Convert two hours to minutes. There are 60 minutes in an hour.

2h * 60mins = 120 mins

Therefore t ≤ 120. Include this into the equation.

120 ≤ 20c + 40s

8 0
2 years ago
Will mark the Brainliest !!!!! A team of 5 boys and 4 girls will be chosen from a group of 16 boys and 13 girls,
vfiekz [6]

Answer:

Step-by-step explanation:

The total number of permutations of boys and girls on the team are:

¹⁶P₅*¹³P₄

1.

Bob will be one of the fixed boys to be picked. Hence, actually 4 boys are to be picked from 15. The permutations of girls being picked remains the same.

Probability = Permutations with Bob as one of the boys / Total permutations

Probability = (¹⁵P₄*¹³P₄) / (¹⁶P₅*¹³P₄) = ¹⁵P₄ / ¹⁶P₅

Probability = \frac{15!}{(15-4)!}/\frac{16!}{(16-5)!} = 15! / 16! = 1/16

2.

Now, Bob is one of the fixed boys and Jane is one of the fixed girls. Hence, actually 4 boys are to be picked from 15 and 3 girls are to be picked from 12.

Probability = Permutations with bob as one of the boys and jane as one of the girls / Total permutations

Probability = (¹⁵P₄*¹²P₃) / (¹⁶P₅*¹³P₄) = (1/16)*(1/13) = 1/208

3.

Now, the probability that at least Jane or Bob will be picked has been asked. This probability is a combination of three probabilities:

Probability = (Probability that only Bob will be picked) + (Probability that only Jane will be picked) + (Probability that both will be picked)

Probability = 1/16 + 1/13 + 1/208 = 0.123

4.

Total teams possible = ¹⁶P₅*¹³P₄ = 8994585600 teams are possible

5 0
3 years ago
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