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3 years ago

If f(x) = 3x + 3, g(x) = 3x + 3, and h(x) = x + 3, what is [g o f o h](–5)?

2 answers:

8 0

The answer would be -6.
Start by substituting -5 into the 'h' function.
h(-5) = -5 + 3 = -2
Now substitute this answer into the 'f' function.
f(-2) = 3(-2) + 3 = -3
now substitute this answer into the 'g' function
g(-3) = 3(-3) + 3 = -6
D is your answer

spayn [35]3 years ago

8 0

Answer:

The correct answer is D. -6

Step-by-step explanation:

f(x) = 3x + 3

g(x) = 3x + 3

h(x) = x + 3

We need to find : [g o f o h](–5)

⇒ [g o f o h](–5)

⇒ [g o f]h(-5)

⇒ [g o f](-5 + 3)

⇒ [g o f](-2)

⇒ [g]f(-2)

⇒ [g](3 × -2 + 3)

⇒ [g](-6 + 3)

⇒ g(-3)

⇒ 3 × -3 + 3

⇒ -9 + 3

⇒ -6

Therefore, The correct answer is D. -6

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A card is drawn at random from a deck of 52 playing cards. Find the probability that the card drawn is:

melomori [17]

probability that the card drawn is:

an ace or a king = 0.1538
a king or a diamond = 0.3269

<u>Step-by-step explanation:</u>

Here we have , A card is drawn at random from a deck of 52 playing cards. We need to find that Find the probability that the card drawn is:

an ace or a king

A deck of standard 52 cards contain four aces. There are four kings in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{8}{52}$

⇒ $probability = 0.1538$

a king or a diamond

A deck of standard 52 cards contain four kings. There are 13 Diamonds in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{(13+4=17)}{52}$