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neonofarm [45]
3 years ago
8

My little brother needs help

Mathematics
2 answers:
IRISSAK [1]3 years ago
7 0
28 is the third one and 26 are the answers 
Anna35 [415]3 years ago
4 0
28 and 26 I hope this one helps Thanks
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What is the area of the polygon??
muminat
B 95.5 hope it helps
6 0
3 years ago
Simplify the expression (8x^3y^2/4a^2b^4)^-2
icang [17]
Simplify the following:
((8 x^3 y^2 a^2 b^4)/4)^(-2)
8/4 = (4×2)/4 = 2:
(2 x^3 y^2 a^2 b^4)^(-2)
Multiply each exponent in 2 x^3 y^2 a^2 b^4 by -2:
(x^(-2×3) y^(-2×2) a^(-2×2) b^(-2×4))/(2^2)
-2×3 = -6:
(x^(-6) y^(-2×2) a^(-2×2) b^(-2×4))/2^2
-2×2 = -4:
(y^(-4) a^(-2×2) b^(-2×4))/(2^2 x^6)
-2×2 = -4:
(a^(-4) b^(-2×4))/(2^2 x^6 y^4)
-2×4 = -8:
b^(-8)/(2^2 x^6 y^4 a^4)
2^2 = 4:
Answer: 1/(4 x^6 y^4 a^4 b^8) thus the answer is A
3 0
3 years ago
PLEASE DONT SEND LINKS OR I WILL REPORT! Emily buys meat for a charity event in her community. Chicken costs 4 AED per kg and be
lyudmila [28]

Answer:

21 AED

Step-by-step explanation:

W know the cost of each kind of meat

Chicken = 4 AED

Beef = 3 AED

We also know how much of each we will be buying

Chicken = 3.6 kg

Beef = 2.2 kg

Multiply each price of meat by its respective weight, then add the products together for you final answer.

4(3.6) + 3(2.2) = 21

5 0
3 years ago
What is the perimeter<br><br><br> This Pythagorean theorem
Elenna [48]

Answer:

a is 5 so the perinmeter is 30

6 0
3 years ago
Please someone answer this please
gladu [14]

Option C:

\frac{3 a^{2} b^{11}}{2 } is equivalent to the given expression.

Solution:

Given expression:

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}

To find which expression is equivalent to the given expression.

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}

Using exponent rule: \frac{1}{a^m}=a^{-m}, \ \  \frac{1}{a^{-m}}=a^{m}

    $=\frac{-18 a^{-2} b^{5}a^{4} b^{6}}{-12 }

    $=\frac{-18 a^{-2} a^{4} b^{5} b^{6}}{-12 }

Using exponent rule: {a^m}\cdot{a^n}=a^{m+n}

    $=\frac{-18 a^{(-2+4)} b^{(5+6)}}{-12 }

   $=\frac{-18 a^{2} b^{11}}{-12 }

Divide both numerator and denominator by the common factor –6.

   $=\frac{3 a^{2} b^{11}}{2 }

$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}=\frac{3 a^{2} b^{11}}{2 }

Therefore, \frac{3 a^{2} b^{11}}{2 } is equivalent to the given expression.

Hence Option C is the correct answer.

8 0
4 years ago
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