I need help with this please I’ve done this question so many times and I keep on getting false answers
1 answer:
Answer:
a=-1 b=3 h=-4 k=5. Hope this helps.
Step-by-step explanation:
We need to find transformations from f(x) to g(x).
K is formula usually means vertical shift. Vertical shift are usually at right end of formula. f(x) has a vertical shift of zero, while g(x) vertical shift is 5. So our k is 5.
h represent our horizontal shift in a equation.
Our horizontal shift is opposite of the sign given.
F(x) has no hoeinzontal shift, while g(x) has x+4.
Set x+4=0
so our h is -4.
B represent our horizontal compression or stretch.
Our horizontal compression/stretch is reciprocal of our b given.
f(x) has no compression or stretch, while g(x) has 1/3x.
Set 1/3x to one.
so our b is 3.
A represents the vertical compression/ stretch. F(x) doesnt have one but G(x) does.
Since it has just a negative sign in front of it, the compression is -1 so a=-1
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Complete Question:
300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a dog, 180 have a cat, and 150 have a cat and a dog. Using this information, answer each of the following questions, Let D be the event that a randomly selected student has a dog and C be the event that a randomly selected student has a cat.
a . What is P(D), the probability that a student in the class has a dog?
b. What is P(C), the probability that a student in the class has a cat?
c. What is P(D and C), the probability that a student in the class has a dog and a cat?
d. What is P(D or C), the probability that a student in the class has a dog or a cat?
Answer:
a. 2/3
b) 3/5
c) 1/2
d) 19/ 15 = 1 4/15
Step-by-step explanation:
The formula for probability =
Number of possible outcomes ÷ Number of events.
Total number of Students = 300
Number of Students that have a dog = 200
Number of Students that have a cat = 180
Number of Students that have a dog and cat = 150
a. What is P(D), the probability that a student in the class has a dog?
In the question, the given data is interpreted as :
Number of possible outcomes = 200
Number of events = 300
P(D) = 200/300
= 2/3
Therefore, the probability that a student has a dog = 2/3
b. What is P(C), the probability that a student in the class has a cat?
In the question, the given data is interpreted as :
Number of possible outcomes = 180
Number of events = 300
P(D) = 180/300
= 3/5
Therefore, the probability that a student has a cat = 3/5
c. What is P(D and C), the probability that a student in the class has a dog and a cat?
In the question, the given data is interpreted as :
Number of possible outcomes = 150
Number of events = 300
P(D) = 150/300
= 1/2
Therefore, the probability that a student has a dog and cat = 1/2
d. What is P(D or C), the probability that a student in the class has a dog or a cat?
The is calculated as
P(D) + P(C)
In the above question,
P(D) is calculated as 2/3
P(C) is calculated as 3/5
Therfore, P(D or C), the probability that a student in the class has a dog or a cat is calculated as:
= 2/3 +3/5
= 19/15 = 1 4/15
