Period =2r /b
assume frequency factor meaning angular frequency "b"
then
2r= 2r/b => b=1
A. sine function whose period 2pi radians
65+40÷83=1 which would be the least simplest way to solve it but sorry
How do I find the Q1 and Q3?<br><br>
0,0,1,2,2,3,4,4,4,4,5,6,6,7,7
Angelina_Jolie [31]
Answer:
Q1 = 2
Q3 = 6
Step-by-step explanation:
Mathematically, we have
Q1 = (n + 1)/4 th term
where n is the number of terms
By the count, we have n as 15
Q1 = (15 + 1)/4
Q1 = 4th term
Looking at the arrangement, the 4th term is 2
For Q3
Q3 = 3(n + 1)/4 th term
n = 15
Q3 = 3 * 4 = 12th term
The 12th term is 6
So that is the 3rd quartile
Answer:
3/4 gallon of purple paint left
Step-by-step explanation:
3/8 + 5/8 =8/8
he uses 2/8 so
8/8 - 2/8 = 6/8
3/4 (simplified)
Answer:
61.61
Step-by-step explanation:
In the expression now that we know the value of x and y, we can replace it with its values. So it would look like this.... 43.37 + 18.24. This equals 61.61.
Hope this helps!
