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wel
2 years ago
15

Tell whether the number is evenly divisible by 2, 3, 4, or 9.

Mathematics
2 answers:
insens350 [35]2 years ago
7 0

Answer:

hii

Step-by-step explanation:

alexira [117]2 years ago
4 0
I don’t even know how to do it
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. Which ordered pairs in the form (x, y) are solutions to the equation 7x – 5y = 28?
Brut [27]

we know that

If a ordered pair (x,y) is a solution of the equation, then the ordered pair must satisfy the equation

we have the equation

7x-5y=28

Let's verify all the cases to determine the solution to the problem.

<u>case A)</u> point (-6,-14)

Substitute the values of x and y in the equation

x=-6\\y=-14

7(-6)-5(-14)=28

-42+70=28

28=28 -------> is  true

therefore

The point  (-6,-14) is a solution of the equation

<u>case B)</u> point (-1,-7)

Substitute the values of x and y in the equation

x=-1\\y=-7

7(-1)-5(-7)=28

-7+35=28

28=28 -------> is  true

therefore

The point  (-1,-7) is  a solution of the equation

<u>case C)</u> point (4,10)

Substitute the values of x and y in the equation

x=4\\y=10

7(4)-5(10)=28

28-50=28

-22=28 -------> is not true

therefore

The point (4,10) is not a solution of the equation

<u>case D)</u> point (7,9)

Substitute the values of x and y in the equation

x=7\\y=9

7(7)-5(9)=28

49-45=28

4=28 -------> is not true

therefore

The point  (7,9) is not a solution of the equation

therefore

<u>the answer is </u>

(-6,-14)

(-1,-7)

8 0
3 years ago
Read 2 more answers
Helppppppppppp plsssssss n ty
Alexus [3.1K]

Answer:

C. \frac{1}{8}

C. \frac{1}{32}

Step-by-step explanation:

A unit fraction is a fraction that has 1 as it's numerator and a positive number as it's denominator.

5 0
1 year ago
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Express the following as:<br>ax+by+c=0<br><br>-2x+3y=6​
Cerrena [4.2K]

The expression -22x + 3y = 6 in the form ax + by + c = 0 is -2x + 3y - 6 = 0

<h3>Linear Equations</h3>

The given equation is:

-2x + 3y = 6

Comparing the equation above with ax + by + c = 0

Rewrite -2x + 3y = 6 in the form ax + by + c = 0

-2x + 3y - 6 = 0

If -2x + 3y - 6 = 0 is compared with ax + by + c = 0

a = -2, b = 3, c = -6

Therefore, the expression-22x + 3y = 6 in the form ax + by + c = 0 is -2x + 3y - 6 = 0

Learn more on linear equations here: brainly.com/question/14323743

8 0
2 years ago
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Simplify this expression.
Grace [21]
11x2 would be your answer.
6 0
2 years ago
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Find all possible values of α+
const2013 [10]

Answer:

\rm\displaystyle  0,\pm\pi

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when <u>tanα+tanβ+tanγ = tanαtanβtanγ</u><u> </u>to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =  \tan( \alpha )  \tan( \beta )  \tan( \gamma )  -  \tan( \gamma )

factor out tanγ:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =   \tan( \gamma ) (\tan( \alpha )  \tan( \beta ) -  1)

divide both sides by tanαtanβ-1 and that yields:

\rm\displaystyle   \tan( \gamma ) =  \frac{ \tan( \alpha )  +  \tan( \beta ) }{ \tan( \alpha )  \tan( \beta )    - 1}

multiply both numerator and denominator by-1 which yields:

\rm\displaystyle   \tan( \gamma ) =   -  \bigg(\frac{ \tan( \alpha )  +  \tan( \beta ) }{ 1 - \tan( \alpha )  \tan( \beta )   } \bigg)

recall angle sum indentity of tan:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( \alpha  +  \beta )

let α+β be t and transform:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( t)

remember that tan(t)=tan(t±kπ) so

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm k\pi )

therefore <u>when</u><u> </u><u>k </u><u>is </u><u>1</u> we obtain:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm \pi )

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha  -\beta\pm \pi )

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm \pi

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ \pm \pi  }

<u>when</u><u> </u><u>i</u><u>s</u><u> </u><u>0</u>:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta \pm 0 )

likewise by Opposite Angle Identity we obtain:

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha   -\beta\pm 0 )

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm 0

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ 0  }

and we're done!

8 0
3 years ago
Read 2 more answers
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