According to the side splitting theorem, which of the following proportions is true

Mathematics

1 answer:

allochka39001 [22]3 years ago

6 0

Answer: $\frac{AC}{CE}=\frac{BD}{DE}$

Step-by-step explanation:

1. According to this theorem, when a line is a parallel with one of the sides of the triangle and touch or intersect the other two sides of this triangle, then this two sides are divide proportionally by the line.

2. Keeping the information above on mind, you can see that the line CD is parallel to AB and intersect the sides AE And BE, therefore, you con conclude the following:

$\frac{AC}{CE}=\frac{BD}{DE}$

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Factor:<br><br><br>(m+2)^2−(m+2)+mn·(n+2)+2n(n+2)

bazaltina [42]

ANSWER
${(m + 2)}( {n}^{2} + 2n + m + 1)$

EXPLANATION

The given expression is

${(m + 2)}^{2} - (m + 2) + mn(n + 2) + 2n(n + 2)$

We factor to get,

$= {(m + 2)}(m + 2 - 1) +n (n + 2) (m+ 2)$

This implies that,

$= {(m + 2)}(m + 1) +n (n + 2) (m+ 2)$

We factor further to obtain,

$= {(m + 2)}((m + 1) +n (n + 2))$

or

$= {(m + 2)}( {n}^{2} + 2n + m + 1)$