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GalinKa [24]
3 years ago
6

A doctor has told a patient to take vitamin pills. The patient needs at least 21 units of vitamin A, at least 8 units of vitamin

C, and at least 71 units of vitamin D. The red vitamin pills cost 20 cents each and contain 7 units of A, 1 unit of C, and 7 units of D. The blue vitamin pills cost 40 cents each and contain 2 units of A, 1 units of C, and 10 units of D. How many pills should the patient take each day to minimize the cost?
a.8 red and 0 blue
b. 4 red and 4 blue
c. 5 red and 3 blue
d. 3 red and 5 blue
Mathematics
1 answer:
vesna_86 [32]3 years ago
8 0
A because 1.6 is less than 2.4, 2.2, and 2.6
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Paul and Brett went to math class and were given the same expression to simplify. The expression they were given was 6 + 12 divi
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Solution: We know that:

Paul and Brett went to math class and were given the same expression to simplify. The expression they were given was 6 + 12 divided by 2(3) + 1.

Looking at the solution's by Paul and Brett, we clearly see that the Paul made a mistake at step 3.

6 + 12 ÷ 2(3) + 1

6 + 12 ÷ 6 + 1                       Correct

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According to order of operation's rule, division needs to done before addition.

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KonstantinChe [14]

The half life formula is :

N(t)=N_o(\frac{1}{2})^{\frac{t}{T}}

where N(t) = remaining quantity after t years

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From the problem, we have :

N(t) = 30 grams

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Solve for t :

\begin{gathered} 30=100(\frac{1}{2})^{\frac{t}{674}} \\ \frac{30}{100}=(\frac{1}{2})^{\frac{t}{674}} \\ \frac{3}{10}=(\frac{1}{2})^{\frac{t}{674}} \end{gathered}

Take ln of both sides :

\begin{gathered} \ln (\frac{3}{10})=\ln (\frac{1}{2})^{\frac{t}{674}} \\ \ln (\frac{3}{10})=\frac{t}{674}\ln (\frac{1}{2}) \\ t=\frac{674\ln (\frac{3}{10})}{\ln (\frac{1}{2})} \\ t=1170.71 \end{gathered}

The answer is t = 1170.71 years

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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