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3 years ago

FOR A TEST!! HELP! Complete the similarity ratio for the similar triangles.

Mathematics

1 answer:

tatyana61 [14]3 years ago

7 0

Answer:

add them up

Step-by-step explanation:

add 8 10 10 and 80 25 20

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Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

Please help!! The slope of the line passing through the points (-3, 4) and (4, -1) is ___.

oksano4ka [1.4K]

I hope this helps you

slope=m

(-3,4) x'=-3 y'=4

(4,-1) x"=4 y"=-1

slope formula :

m. (x'-x")=y'-y"

m. (-3-4)=4-(-1)

m.-7=4+1

m=-5/7

4 0

3 years ago

Is Distance is never negative.

stiv31 [10]

Answer:

Yes, distance is never negative.

5 0

3 years ago

Read 2 more answers

You start at (10, 1). You move down 1 unit and left 7 units. Where do you end?

solmaris [256]

Translation in right or left causes the x coordinate to change while translation in up or down causes the y coordinate to change.

Moving left or down causes the coordinates to be going negative.

Moving right or up causes the coordinates to be positive.

Original point (10, 1).

Down 1 unit:

(10, 1 - 1) = (10, 0)

Left 7 units:

(10 - 7, 0) = (3, 0)

You end at (3, 0)

5 0

3 years ago

Victoria counts this week's food donations at a pet shelter. There are 16 full cases of canned food. There are 4 cases of canned

Kryger [21]

Answer:

HOPE THIS HELPS YOU!!!! :D

Step-by-step explanation:

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5 0

3 years ago