Answer:
Option (b) is correct.

Step-by-step explanation:
Given: 
We have too choose the correct simplification for the given statement.
Consider 
Using property of exponents,
We have,

Again applying property of exponents 
We have,

Simplify, we have,

we get,

Thus, 
Option (b) is correct.
Each cupcake would have 3/40 of a pound of nuts since that is 10x smaller than the total they have so they could put that amount into 10 cupcakes.
The answer is 3/40
Answer: 0.1824
Step-by-step explanation:
Given : The mileage per day is distributed normally with
Mean : 
Standard deviation : 
Let X be the random variable that represents the distance traveled by truck in one day .
Now, calculate the z-score :-

For x= 132 miles per day.

For x= 159 miles per day.

Now by using standard normal distribution table, the probability that a truck drives between 132 and 159 miles in a day will be :-

Hence, the probability that a truck drives between 132 and 159 miles in a day =0.1824
Answer:
If we are to treat these as two ordered pairs, then the rate of change is 1.25.
Step-by-step explanation:
To find this, use the slope equation with the ordered pairs.
m(slope) = (y2 - y1)/(x2 - x1)
m = (11 9/16 - 9 1/16)/(12 - 10)
m = (2 8/16)/2
m = 2.5/2
m = 1.25
Now we know that this could be a function since we have a constant slope.
If my multiplication is right the answer is <span>321.625</span>