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pickupchik [31]
3 years ago
8

Please help me with this

Mathematics
1 answer:
alexandr1967 [171]3 years ago
8 0
Photo has the answer

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Karl’s and eddie’s ages added together are equal to 65. 10 years ago, Karl was twice as old as Eddie. How old are they now
trapecia [35]

9514 1404 393

Answer:

  • Karl is 40
  • Eddie is 25

Step-by-step explanation:

10 years ago, the sum of their ages was 65 -2·10 = 45.

If Karl was twice as old as Eddie, his contribution was 2/3 of the sum and Eddie's was 1/3. That is, Karl was (2/3)(45) = 30 and Eddie was 15 at that time.

Now, Karl is 40 and Eddie is 25.

__

This can be solved using a system of equations.

  e = 65 -k

  (k -10) = 2(e -10)

Substituting the first equation into the second gives ...

  k -10 = 2((65 -k) -10)

  k -10 = 110 -2k . . . . . . . simplify

  3k = 120 . . . . . . . . . . . . add 10+2k

  k = 40

  e = 65 -40 = 25

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The four is in the thousandths place. 
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3 years ago
Evaluate x - 20 when x=3
ryzh [129]

Answer:

-17

Step-by-step explanation:

Plug in 3:

3 - 20 =

Solve:

3-20 = -17

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What is two thirds divided into 3
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