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3 years ago

Identify the linear equation.

1 answer:

5 0

The answer is B)y = 1/2x + 3

The solution is y = 1/2x + 3. This is a linear function. Two of the other choices are quadratic functions and the first is an absolute value function.

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how many solutions does the equation 2(2x- 10)-8 =-2(14-3x) have?A.exactly one solution B. exactly two solutions C. no solution

Zarrin [17]

Answer: it has no solutions

Step-by-step explanation:

Factor then solve to find the complex solutions.

5 0

3 years ago

The capacity of a punch bowl is 24 Can you help me find the customary unit for it plz

pashok25 [27]

I belive its Ounces hope this helps

4 0

3 years ago

Pls help me pls pls pls

vovikov84 [41]

Answer: 1x + 2y = 4

Step-by-step explanation:

The equation of the line is y = -1/2x + 2.

First, let's make 4 on one side of the equation. First, bring x to the left. y + 1/2x = 2. Then multiply the whole equation by two. Thus, 1x + 2y = 4.

Hope it helps <3

3 0

3 years ago

1. A clerk is paid P 45.25 per hour for 40 hours a week, 1.50 times the

Ierofanga [76]

Answer:

The clerk's total earnings is P520.375

Step-by-step explanation:

Given

Earnings = $45.25 per hour

Overtime = 1.5 * regular earnings

Holiday = double regular earnings

Required

Determine his earnings for 5 hours (overtime) and 2 hours (holiday)

From the question, we understand that

Regular Earnings = P45.25

Overtime Earnings = 1.5 * P45.25

Overtime Earnings = P67.875

Overtime Earnings for 5 hours = 5 * P67.875

Overtime Earnings for 5 hours = P339.375

Holiday Earnings = 2 * Regular Earnings

Holiday Earnings = 2 * P45.25

Holiday Earnings = P90.5

Holiday Earnings for 2 hours = 2 * P90.5

Holiday Earnings for 2 hours = P181.0

The clerk's total earnings is calculated as thus:

Total = Overtime Earnings for 5 hours + Holiday Earnings for 2 hours

Total = P339.375 + P181.0

Total = P520.375

5 0

3 years ago

Read 2 more answers

X + 2y = 33 x-y = 11

Tasya [4]

Answer:

$x=\frac{55}{3},\:y=\frac{22}{3}$

Step-by-step explanation:

Solve by Substitution ;

$\begin{bmatrix}x+2y=33\\ x-y=11\end{bmatrix}\\\\\mathrm{Isolate}\:x\:\mathrm{for}\:x+2y=33:\quad x=33-2y\\\\\mathrm{Subsititute\:}x=33-2y\\\\\begin{bmatrix}33-2y-y=11\end{bmatrix}\\\\Simplify\\\begin{bmatrix}33-3y=11\end{bmatrix}\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:33-3y=11:\quad y=\frac{22}{3}\\\mathrm{For\:}x=33-2y\\\\\mathrm{Subsititute\:}y=\frac{22}{3}\\x=33-2\times\frac{22}{3}\\\\x=\frac{55}{3}\\\\x=\frac{55}{3},\:y=\frac{22}{3}$

7 0

3 years ago