1. Find the length, width, and height of the rectangular prism.
2. Multiply the length, width, and height.
3. Write the answer in cubic units. For example: 60 inches3.
The length is the longest side of the flat surface of the rectangle on the top or bottom of the rectangular prism.
Ex: Length = 5 in.
<span>The width is the shorter side of the flat surface of the rectangle on the top or bottom of the rectangular prism. <span>Ex: Width = 4 in.The height is the part of the rectangular prism that rises up. Imagine that the height is what stretches up a flat rectangle until it becomes a three-dimensional shape. <span>Ex: Height = 3 in.You can multiply them in any order to get the same different result. The formula for finding the volume of a rectangular prism is the following: Volume = Length * Height * Width, or V = L * H * W. <span>Ex: V = 5 in. * 4 in. * 3 in. = 60 in.Since you're calculating volume, you're working in a three-dimensional space. Just take your answer and state it in cubic units. Whether you're working in feet, inches, or centimeters, you should state your answer in cubic units. <span>60 will become 60 in3.</span></span></span></span><span><span><span><span>
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Pythagoras theorem: leg 1 squared + leg 2 squared = hypotenuse squared
In the diagram, the triangle has angles 90 and 45. So the other angle in the triangle must be 45 degrees as well. (180 - 90 -45 = 45)
This means it is an isosceles triangle (since two angles are the same), so the two legs have the same length.
So we can say that length of leg1 = x, and the length of leg2 also equals x
Now let's use pythagoras' theorem:
leg1 = x
leg2 = x
hypotenuse = 16
x^2 + x^2 = 16^2
2x^2 = 16^2
2x^2 = 256
x^2 = 128
x = √(128)
x = 8√2
Answer: 2/3
Step-by-step explanation: You take the 2 and divided it by 3 but your going to get a long decimal so you can put it into a fraction of 2/3
Answer: 
Step-by-step explanation:
Since, The total number of student = 300
Out of which,
The number of students who are only in Maths = 120
And, The number of students who are only in Science = 50
While, the students who are not from any subject = 100
Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None
= 300 - 120 - 50 - 100
= 30
That is, there are 30 students who are both from science and maths,
Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10
