Combine the like terms to create an equivalent expression 3y+6-y

What’s in a equation or Leniar function y axis 1 and negative 7 and x axis negative 3 and 1

Elodia [21]

A linear function is an algebraic equation in which each term is either a constant or the product of a constant and (the first power of) a single variable. For example, a common equation,

y

=

m

x

+

b

, (namely the slope-intercept form, which we will learn more about later) is a linear function because it meets both criteria with

x

and

y

as variables and

m

and

b

as constants. It is linear: the exponent of the

x

term is a one (first power), and it follows the definition of a function: for each input (

x

) there is exactly one output (

y

). Also, its graph is a straight line.

5 0

3 years ago

What is the measure of JL?<br> А. 16°<br> В. 64°<br> с. 148<br> D. 32°

enyata [817]

Answer:

Step-by-step explanation:

4 0

3 years ago

Simplify the expression

MaRussiya [10]

11) 7 + -10+(4(5+-3)) = 7+-10+8=5

12) (12 +-10)+3x+-1(2x+4x), 12+-10x+3x+-2x+-4x = 12+-13x

5 0

3 years ago

Read 2 more answers

How to solve y=3(0)^2-6(0)-5

Ilya [14]

Y = - 5

I hope this helps. :)

8 0

3 years ago

Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an

Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is the mean life expectancy, $\sigma$ is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean $\mu$ , standard deviation $\sigma$ .

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is the mean life expectancy, $\sigma$ is the standard deviation and n is the size of the sample.

8 0

3 years ago