X = jane, y = jasmine, z = jocelyn
x + y + z = 56
x = 3z
y = 2z + 2
3z + 2z + 2 + z = 56
6z + 2 = 56
6z = 56 - 2
6z = 54
z = 54/6
z = 9 <==== jocelyn
x = 3z
x = 3(9)
x = 27 <=== jane
y = 2z + 2
y = 2(9) + 2
y = 18 + 2
y = 20 <=== jasmine
The probability that the Yankees will lose when they score fewer than 5 runs is 17.16%.
<h3><u>Probability </u></h3>
Given that this season, the probability that the Yankees will win a game is 0.61 and the probability that the Yankees will score 5 or more runs in a game is 0.56, and the probability that the Yankees win and score 5 or more runs is 0.44, to determine what is the probability that the Yankees will lose when they score fewer than 5 runs the following calculation must be made:
- 1 - 0.61 = 0.39
- 1 - 0.56 = 0.44
- 0.39 x 0.44 = X
- 0.1716 = X
Therefore, the probability that the Yankees will lose when they score fewer than 5 runs is 17.16%.
Learn more about probability in brainly.com/question/11234923
#SPJ1
To find your answer you must add them all together :
17,689
1,614
+ 176
_________
19,479
Answer:
1 fact per 3 seconds because you divide 300 by 100
