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sladkih [1.3K]
3 years ago
6

How do I work this problem​

Mathematics
1 answer:
agasfer [191]3 years ago
5 0

Answer:

You solve it

Step-by-step explanation:

no problem was given. \_(•_•)_/

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A certain circle can be represented by the following equation. x^2+y^2+18x+14y+105=0 What is the center of the circle? What is t
Gre4nikov [31]

Answer:

See below.

Step-by-step explanation:

Recall the equation for a circle:

(x-h)^2+(y-k)^2=r^2, where (h,k) is the center and r is the radius.

We need to turn the given equation into the above format. We do this by completing the square.

First, group them:

(x^2+18x)+(y^2+14y)=-105

For the first section, complete the square for x^2+18x:

x^2+18x+81-81

(x+9)^2-81

Do the same for the second:

y^2+14y

y^2+14y+49-49

(y+7)^2-49

All together:

((x+9)^2-81)+((y+7)^2-49)=-105

(x+9)^2+(y+7)^2-130=-105

(x+9)^2+(y+7)^2=25

The center is (-9,-7).

The radius is \sqrt{25}=5

5 0
3 years ago
I need help with this problemmm, someone help mee!!.
Varvara68 [4.7K]

Answer:

∠A=30°

Step-by-step explanation:

let's call the angle at the bottom B and the one next to the 130 C

∠A=3x-6

∠C=180-130= 50°

vertical angles are equal∠B =8x+4

∠A+∠C+∠B=180°

find x:

3x-6+50+8x+4= 180°

11x+48=180°

11x= 132

x=12

find ∠A

∠A=3x-6= 3(12)-6 =30°

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3 years ago
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Answer:

below

Step-by-step explanation:

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5) 400

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9) 50

10) 7000

11) 8

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2 years ago
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hodyreva [135]

125.13

Step-by-step explanation:

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3 years ago
Fill in the missing numbers on the number line. It starts at 2/5 and end at 5.
erastovalidia [21]
2 1/2, 3, 3 1/2, 4, 4 1/2, 5

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