Given the expotential function f(x) = 4(3)^x find f(0) and f(1)
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Answer:
the function given
for 4 units up, just add 4 as a constant
4 units up means, every old value will now be 4 more than previous value. at x=0, y=0 in the transformed curse it should x=0 and y=4, so just add it.
for 6 units left,
each old value of y should now occur 6 units before the old value of x i.e. X=x+6
for example, the point (0,0) should occur at (-6,0) in the transformed graph,
hence,
so the final curve is