Question

Given the expotential function f(x) = 4(3)^x find f(0) and f(1)

Answer 1

Answer:

4 and 12

Step-by-step explanation:

Given

f(x) = 4$(3)^{x}$ , then

f(0) = 4$(3)^{0}$ = 4 × 1 = 4 [ $a^{0}$ = 1 ]

f(1) = 4$(3)^{1}$ = 4 × 3 = 12