If the squares are 4 inches then the height of the sides will be 4 inches, so you multiply the area of the base times 4!
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
Answer:
x= -5 y= -1
Step-by-step explanation:
3/8y = 9/24 since 3*3=9 and 8*3=24
4 = 64/16 since 16*4=64
3z/x = 9z/3x since 3z*3=9z and x*3=3x
To solve for x
bx=-7
divide b on both sides
x=-7/b
to solve for b
bx=-7
divide x on both sides
b=-7/x
