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Nostrana [21]
3 years ago
10

What is the smallest number that appears in both rows this number is said to be the least common multiples of 2 and 3

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0
The least common multiples of 2 and 3 would be 2 and 1 also 2 and is at its lowest multiple
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A rectangular-prism-shaped toy box is 2 cm by 1 cm by 1 cm. a storage bin is packed with 18 of these toy boxes. there is no extr
Virty [35]
The bin's volume is 36cm³
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3 years ago
Which expression is equal to 16.25 ÷ 2.5?
kirza4 [7]
6.5 is the answer to your question
6 0
3 years ago
Which statement correctly describes a net?
charle [14.2K]
<h2>Answer:</h2>

A) A net is a two-dimensional pattern for a solid.

<h2>Step-by-step explanation:</h2>

In fact, a net is a two-dimensional pattern for a solid. But what is a solid? They are three-dimensional shapes. Prisms, cubes, pyramids, among others, are examples of solids. For example, the first figure below is a net because is a two dimensional patter for a pyramid which is shown in the second figure. As you can see, the first figure is a two-dimensional patter for this three-dimensional shape. Hence, by unfolding the pyramid we get the net or, in other word, by folding the net we get the pyramid.

3 0
3 years ago
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
Put these decimals from least to greatest<br> 8.37 8.3 8.219 8.129
patriot [66]
8.129
8.219
8.3
8.37

Always go from left to right as compare the values in the tenth, then hundredths, then thousandths place. Remember that if there is no digit, it is a 0 (after the decimal of course).
7 0
3 years ago
Read 2 more answers
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