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3 years ago

Ted's debt is 14 less than half of Mike's debt. If we let w represent Mike's debt, write an algebraic expression for Ted's debt.

Mathematics

1 answer:

Temka [501]3 years ago

3 0

Answer:

t = (1/2)m - 14

Step-by-step explanation:

"Ted's debt is 14 less than half of Mike's debt" translates into

t = (1/2)m - 14, where m is Mike's debt and t is Ted's.

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10 + 2(7 - 9x) = 5(2x - 12)<br><br><br>Full steps as well please

blagie [28]

Answer:

x = 3

Step-by-step explanation:

10 + 2(7 - 9x) = 5(2x - 12)

10 + 14 - 18x = 10x - 60

24 - 18x = 10x - 60

+60 +60

-------------------------------------

84 - 18x = 10x

+18x +18x

-------------------------------------

84 = 28x

/28 /28

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3 = x

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3 years ago

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Answer:

(w+4) (w-4)

Step-by-step explanation:

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Which equation has a graph that lies entirely above the x-axis?

Tanzania [10]

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0, 7, 14, 21, next three terms

Nat2105 [25]

Answer:

28, 35, 42

Step-by-step explanation:

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3 years ago

What is true about the solution above.

Masja [62]

ANSWER

$x = \pm \sqrt{3}$

and they are actual solutions.

EXPLANATION

The given equation is:

$\frac{ {x}^{2} }{2x - 6} = \frac{9}{6x - 18}$

Cross multiply

${x}^{2} (6x - 18) = 9(2x -6 )$

This implies;

${x}^{2} (6x - 18) - 9(2x - 6) = 0$

$3{x}^{2} (2x - 6) - 9(2x - 6) = 0$

Factor

$(3 {x}^{2} - 9)(2x - 6) = 0$

$3 {x}^{2} - 9 = 0 \: or \: 2x - 6= 0$

$3 {x}^{2} = 9 \: or \: 2x = 6$

${x}^{2} = 3\: or \: x = 3$

${x} = \pm \sqrt{3} \: or \: x = 3$

The domain of the given equation is

$x \ne3$

Therefore the actual solutions are

$x = \pm \sqrt{3}$

NB: x=3 is not in the domain of the given equation. It cannot be an extraneous solution.

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3 years ago