Answer:
Degree = 4
Step-by-step explanation:
For the given conditions:
n = 4
i and 5i are zeros
f(-2) = 145
For zeros, it means they are a quadratic factor of the expression
It means, we will have x = ± i and x = ± 5i
therefore, the given factors are (x - i)(x + i)(x - 5i)(x + 5i)
Hence, we have the function
given degree = 4
f(x) = a(x-i)(x+i)(x-5i)(x+5i)
f(x) = a(x² + 1)(x² + 25)
Hence, substituting -2 for x, we have
f(-2) = a(5)(29) = 145
Hence, a = 1
f(x) = x⁴ + 26x² + 25
Therefore, we can see that the given degree = 4
I put A, D, and E but Im not sure if they are correct
Answer:
9
Step-by-step explanation:
<u><em>Definition of: Coefficient</em></u>
A number used to multiply a variable.
<u><em>Example:</em></u> 6z means 6 times z, and "z" is a variable, so 6 is a coefficient.
Variables with no number have a coefficient of 1.
<u><em>Example</em></u>: x is really 1x.
<em><u>coefficients:</u></em>
3<em>x⁴</em>+ 5<em>x²</em> + 1<em>x</em>
<u><em>sum of the coefficients:</em></u>
3 + 5 + 1
8 + 1
9
Answer:
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D0.03926%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
Step-by-step explanation:
To find : Convert
into ![\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
Solution :
We convert units one by one,
![1\text{ m}^2=10.7639\text{ ft}^2](https://tex.z-dn.net/?f=1%5Ctext%7B%20m%7D%5E2%3D10.7639%5Ctext%7B%20ft%7D%5E2)
![1\text{ sec}=\frac{1}{3600}\text{ hour}](https://tex.z-dn.net/?f=1%5Ctext%7B%20sec%7D%3D%5Cfrac%7B1%7D%7B3600%7D%5Ctext%7B%20hour%7D)
![1\text{ cal}=0.003968\text{ BTU}](https://tex.z-dn.net/?f=1%5Ctext%7B%20cal%7D%3D0.003968%5Ctext%7B%20BTU%7D)
Converting temperature unit,
![^\circ C\times \frac{9}{5}+32=^\circ F](https://tex.z-dn.net/?f=%5E%5Ccirc%20C%5Ctimes%20%5Cfrac%7B9%7D%7B5%7D%2B32%3D%5E%5Ccirc%20F)
![1^\circ C\times \frac{9}{5}+32=33.8^\circ F](https://tex.z-dn.net/?f=1%5E%5Ccirc%20C%5Ctimes%20%5Cfrac%7B9%7D%7B5%7D%2B32%3D33.8%5E%5Ccirc%20F)
So, ![1^\circ C=33.8^\circ F](https://tex.z-dn.net/?f=1%5E%5Ccirc%20C%3D33.8%5E%5Ccirc%20F)
Substitute all the values in the unit conversion,
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D%5Cfrac%7B0.003968%7D%7B10.7639%5Ctimes%20%5Cfrac%7B1%7D%7B3600%7D%5Ctimes%2033.8%7D%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D%5Cfrac%7B0.003968%7D%7B0.101061%7D%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D0.03926%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
Therefore, The conversion of unit is ![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D0.03926%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
Answer:
○ C. ![\displaystyle 0, 2, and\:4](https://tex.z-dn.net/?f=%5Cdisplaystyle%200%2C%202%2C%20and%5C%3A4)
Step-by-step explanation:
Wherever the graph intersects the x-axis is considered your zero [x-intercept], therefore you have your answer:
![\displaystyle [0, 0], [2, 0], and\: [4, 0]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B0%2C%200%5D%2C%20%5B2%2C%200%5D%2C%20and%5C%3A%20%5B4%2C%200%5D)
I am joyous to assist you at any time.