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Cloud [144]
3 years ago
6

PLEASE IF YOU ARE SMART HELP ME WITH THIS PROBLEM. I WILL GIVE YOU EXTRA POINTS

Mathematics
1 answer:
raketka [301]3 years ago
3 0
a_{n} = 2a_{n-1} + 3

a_{1} = 2

a_{2} = 2a_{2-1} + 3 = 2a_{1} + 3 = (2*2) + 3 = 4 + 3 = 7

a_{3} = 2a_{3-1} + 3 = 2a_{2} + 3 = (2*7) + 3 = 14 + 3 = 17

a_{4} = 2a_{4-1} + 3 = 2a_{3} + 3 = (2*17) + 3 = 34 + 3 = 37

a_{5} = 2a_{5-1} + 3 = 2a_{4} + 3 = (2*37) + 3 = 74 + 3 = 77

Hence, the first five terms are 2, 7, 17, 37, 77.
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DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

<h3>Congruent shape</h3>

Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.

Given that DE = AB and BC = EF.

In right triangle DEF, using Pythagoras:

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