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2 years ago

What is the circumference of circle T

Mathematics

1 answer:

gayaneshka [121]2 years ago

8 0

You know that the <span>circumference of a circle is 2 x 3.14 x r right?
So the answer is 25.12.</span>

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7. Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6). Determine whether

kirill [66]

Answer:

SQUARE

Step-by-step explanation:

If Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6).

Find the following MN, NP, PQ and MQ

Using the formula for calculating the distance between two points

MN = √(6-0)²+(0-4)²

MN = √6²+4²

MN = √36+16

MN = √52

MN = 2√13

NP = √(0-6)²+(-4-0)²

NP = √6²+4²

NP = √36+16

NP = √52

NP = 2√13

PQ = √(-6-0)²+(0-(-4))²

PQ = √6²+4²

PQ = √36+16

PQ = √52

PQ = 2√13

MQ = √(-6-0)²+(0-4)²

MQ = √6²+4²

MQ = √36+16

MQ= √52

MQ = 2√13

Since the length of all the sides are equal, hence the shape is a SQUARE

4 0

1 year ago

How would I figure out a linear equation with two plot points with fractions? (1/3(6),3) and (1/2(19),-2) are my two plot points

murzikaleks [220]

Answer: $m=\frac{-30}{79},\ y=5.40$

Step-by-step explanation:

Given

Points are $\left(6\frac{1}{3},3\right),\ \left(19\frac{1}{2},-2\right)$

Convert mixed numeral to fraction

$\left(6\frac{1}{3},3\right)\Rightarrow \left(\dfrac{19}{3},3\right)\\\\\left(19\frac{1}{2},-2\right)\Rightarrow \left(\dfrac{39}{2},-2\right)$

Slope of the line is

$\Rightarrow m=\dfrac{3-(-2)}{\dfrac{19}{3}-\dfrac{39}{2}}\\\\\Rightarrow m=\dfrac{5}{\dfrac{38-117}{6}}\\\\\Rightarrow m=\dfrac{-30}{79}$

Equation of line

$\Rightarrow \dfrac{y-3}{x-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\text{for y-intercept, put x=0}\\\\\Rightarrow \dfrac{y-3}{0-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\Rightarrow y-3=\dfrac{190}{79}\\\\\Rightarrow y=3+2.40\\\Rightarrow y=5.40$

3 0

2 years ago

Find (x+3) (x^2 - 2x -8). Write answer in standard form

Pavlova-9 [17]

Answer:

x3+x2-14x-24

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Please help! I’ll mark brainliest

Usimov [2.4K]

Answer: 19 ≥ 3z + 1 ≥ - 5

8 0

2 years ago

Plot the image of D under a dilation about the origin (0,0) with a scale factor of 2

ElenaW [278]

(-6,-4)

If you dilate a point, (c,d) about (a,b) by a scale factor by k. You'll going to subtract each coordinates where the point will be dilated about (a,b) from the point (c,d) and then multiply them by k. This would be the formula if you want: (k(c -a), k(b -d))

Let's say F is the dilation of D about the origin or (0,0) then the x coordinate of F would be

$x = 2( - 3 - 0) \\ x = 2( - 3) \\ x = - 6$

This would be the y coordinate of F:

$y = 2( - 2 - 0) \\ y = 2( - 2) \\ y = - 4$

Thus the coordinates of F is (-6,-4)

4 0

2 years ago