Answer:
D. (x-5)^2 = 36
Step-by-step explanation:
If you add 11 to the given equation, you get ...
x^2 -10x = 11
Then you can add the square of half the x-coefficient to complete the square.
x^2 -10x +25 = 11 +25
(x -5)^2 = 36 . . . . simplify to the appropriate form
Answer:
Remove parentheses. xy³
z^4
4Step-by-step explanation:
<h3>
Answer: n = -11</h3>
=========================================================
Explanation:
Since x-2 is a factor of f(x), this means f(2) = 0.
More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.
So if we plugged x = 2 into f(x), we'd get
f(x) = x^3+x^2+nx+10
f(2) = 2^3+2^2+n(2)+10
f(2) = 8+4+2n+10
f(2) = 2n+22
Set this equal to 0 and solve for n
2n+22 = 0
2n = -22
n = -22/2
n = -11 is the answer
Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10
Plug x = 2 into that updated f(x) function to find....
f(x) = x^3+x^2-11x+10
f(2) = 2^3+2^2-11(2)+10
f(2) = 8+4-22+10
f(2) = 0
Which confirms our answer.
<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) 
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = 
Hence, p(getting 2 good coil for two selection) = 
800
You would multiply 10x80
