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I am Lyosha [343]
2 years ago
12

I NEED HELP PLSSS!!!

Mathematics
1 answer:
Aloiza [94]2 years ago
8 0
2.4•10^-10

the dot is the multiplication symbol and the -10 is the exponent
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Step-by-step explanation:

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What is the surface area of the pyramid?
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What is the solution of the system x − 3y = –13 and 5x + 7y = 34? A. `x = (6)/(5)`, y = 4 B. `x = (7)/(2), y = (9)/(2)` C. `x =
Masteriza [31]

For this case we have the following system of equations:

x-3y = -13\\5x + 7y = 34

From the first equation we clear "x":

x = -13 + 3y

We substitute in the second equation:

5 (-13 + 3y) + 7y = 34

We apply distributive property:

-65 + 15y + 7y = 34

We add similar terms:

-65 + 22y = 34

We add 65 to both sides:

22y = 34 + 65\\22y = 99

We divide between 22 on both sides:

y = \frac {99} {22}\\y = \frac {9} {2}

We look for the value of the variable "x":

x = -13 + 3 \frac {9} {2}\\x = -13 + \frac {27} {2}\\x = \frac {-26 + 27} {2}\\x = \frac {1} {2}

Thus, the solution of the system is:

(x, y): (\frac {1} {2}, \frac {9} {2})

ANswer:

(x, y): (\frac {1} {2}, \frac {9} {2})

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3 years ago
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A state end-of-grade exam in American History is a multiple-choice test that has 50 questions with 4 answer choices for each que
Assoli18 [71]

Answer:

Q1) The student has a 0.01% probability of passing the test.

Q2) She has a 99.91% probability of passing in the test.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he gets it correct, or he gets it wrong. So we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For this problem, we have that:

Question 1.

There are 50 questions, so n = 50.

The student is going to guess each question, so he has a \pi = \frac{1}{4} = 0.25 probability of getting it right.

He needs to get at least 25 question right.

So we need to find P(X \geq 25).

Using a binomial probability calculator, with n = 50 and \pi = 0.25 we get that P(X \geq 25) = 0.0001.

This means that the student has a 0.01% probability of passing the test.

Question 2.

Now, we need to find P(X \geq 25) with \pi = 0.70. So P(X \geq 25) = 0.9991

She has a 99.91% probability of passing in the test.

7 0
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