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Gekata [30.6K]
3 years ago
5

Answer please for me babes

Mathematics
1 answer:
Wittaler [7]3 years ago
5 0
I hope you figure it out! I would say it is x is greater than negative 0.10 but I do not know
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T-T im so sad becuase i have a 76 in my grade book thingy and my parents want at least an 80 but my teacher is super duper stric
ratelena [41]

Answer:

awww bub

Step-by-step explanation:

some people just are a holes. they will get over it, a c isn't gonna kill them or you. eventually they'll forget it. i know it tough with stricter parents. that's my mother for you. they might yell they might scream but in the end it dosnt matter. school dosnt measure your smarts. it measures how well you can remember a lecture they gave you a week ago and expect you to memorize it. its ok. you'll be ok. as long as you can tell yourself truthfully you did your best then there is nothing more to it. you got this. i believe in you :)

4 0
2 years ago
Read 2 more answers
Would I distribute or foil first -2(b-2)(b-2)
7nadin3 [17]
You would distribute the -2 and the first b-2
-2xb= -2b
-2x-2= 2
So it would now be -2b - 2 (b-2)
7 0
3 years ago
X squared divided by -10 =2<br> what is
lesya [120]

Hey there!

The answer to your question is ± 12

To solve the equation x²/-10 = 2, first multiply 10 to both sides:

x² = 20

Then, take the square root from both sides:

x = ± 20

4 0
2 years ago
A coin is tossed 3 times. What is the probability that the number of tails obtained will be between 1 and 3 inclusive?
LekaFEV [45]

Answer: \dfrac{7}{8}

Step-by-step explanation:

Given : When a coin is tossed twice , the total outcomes will become

HHH , HHT , HTH , THH , TTH , THT , HTT ,TTT

Total outcomes = 8

Favorable outcomes to obtain 1 and 3 inclusive = HHT , HTH , THH , TTH , THT , HTT ,TTT

Number of favorable outcomes = 7

Probability that the number of tails obtained will be between 1 and 3 inclusive = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

=\dfrac{7}{8}

Hence, the probability that the number of tails obtained will be between 1 and 3 inclusive =\dfrac{7}{8}

5 0
3 years ago
How many inches longer is a hercules beetle than a ladybug
Mila [183]

Answer:

A Hercules Beetle is 6.97 inches larger than A ladybug

Step-by-step explanation:

A hercules beetle is 7 inches long while a ladybug is about 0.03 cm long when subtracting these two you will get a grand total of 6.97.

6 0
2 years ago
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