Ask question

Ask question

All categories

snow_tiger [21]

2 years ago

8

Jared is 10 years old, and Peter is 15 years old. Together, they run 150 yards. How far does each brother run. if a brother is t

wice the age they run 2 times as far

1 answer:

Andreas93 [3]2 years ago

8 0

Jared can run 75 yards and Peter can run 125 yards

You might be interested in

ANSWER FAST PLEASE 20 POINTS !!!<br> Where will this shape be after a reflection in the line y = x?

Andre45 [30]

Answer:

is easy just reflected y-intercept to x-intercept

5 0

2 years ago

Read 2 more answers

Factorise y^2-10y+16

KatRina [158]

I hope this helps you

8 0

3 years ago

Differentiate x^2/4-x^3

Ede4ka [16]

Answer:

x^4 + 8x

-----------------

(4-x^3)^2

Step-by-step explanation:

d /dx (x^2/(4-x^3))

When we differentiate a fraction u/v

df/dx = u/v

= v du/dx-u dv/dx

---------------------------

v^2

we know u = x^2 so du/dx = 2x

v = (4-x^3) so dv/dx = -3x^2

d dx = (4-x^3) (2x)- x^2 ( -3x^2)

-------------------------------------

(4-x^3)^2

Combining terms

(8x-2x^4) --3x^4

-------------------------------------

(4-x^3)^2

8x-2x^4 +3x^4

-------------------------------------

(4-x^3)^2

x^4 + 8x

-------------------------------------

(4-x^3)^2

8 0

3 years ago

A news vendor sells newspapers and tries to maximize profits. The number of papers sold each day is a random variable. However,

SOVA2 [1]

Let me think this through again and I will come back to you! 2.22 graph

4 0

3 years ago

In its monthly report, the local animal shelter states that it currently has 24 dogs and 18 cats available for adoption. Eight o

andrezito [222]

Answer with Step-by-step explanation:

We are given that

Total dogs=24

Total cats=18

Total animals=24+18=42

Male dogs=8

Male cats=6

Total male animals=8+6=14

Total female animals=42-14=28

Female cats=18-6=12

Dogs female=24-8=16

a.We have to find the probability that the pet is male, given that it is cat.

It means we have to find P(Male/cat)

Conditional probability: $P(A/B)=\frac{P(A\cap B)}{P(B)}$

P(Cat)= $\frac{18}{42}$

$P(male cat)=\frac{6}{42}$

$P(Male/cat)=\frac{\frac{6}{42}}{\frac{18}{42}}$

P(male/cat)= $\frac{6}{18}=0.33$

b. $P(female cat)=\frac{12}{42}$

$P(female)=\frac{28}{42}$

$P(Cat/Female)=\frac{\frac{12}{42}}{\frac{28}{42}}=\frac{12}{28}=0.43$

c.P(Dog)= $\frac{24}{42}$

$P(dog female)=\frac{16}{42}$

$P(female/dog)=\frac{\frac{16}{42}}{\frac{24}{42}}$

$P(female/dog)=\frac{16}{24}=0.67$

5 0

3 years ago