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3 years ago

Which equation is represented by the graph below?

Mathematics

1 answer:

gregori [183]3 years ago

6 0

Answer:

y = e^x - 4

Step-by-step explanation:

The missing options are

y = ln x - 3

y = ln x - 4

y = e^x - 3

y = e^x - 4

The function is defined in quadrant 3 and increases exponentially, then it is not a logarithm.

f(x) crosses the y-axis at (0, -3). Replacing x = 0 the last option, we get:

y = e^0 - 4 = 1 - 4 = -3

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aev [14]

Answer:

A ) The money which Andre pay for the bike is $ 67.30

B ) The money which Andre pay for the bike is $ 76.92

Step-by-step explanation:

Given as :

The wholesale cost or market price of the bike = m.p = $ 96.15

A ) The discount percentage = 30 %

Let The selling price of the bike after discount = s.p

Now ,

Discount % = $\dfrac{m.p - s. p }{m . p}$

or, 30 % = 1 - $\dfrac{s. p }{m . p}$

or, $\dfrac{30 }{100}$ = 1 - $\dfrac{s. p }{96.15}$

Or, $\dfrac{s. p }{96.15}$ = 1 - $\dfrac{30 }{100}$

or, $\dfrac{s. p }{96.15}$ = $\dfrac{100 - 30 }{100}$

Or, $\dfrac{s. p }{96.15}$ = $\dfrac{70}{100}$

Or, s. p = $\dfrac{70}{100}$ × 96.15

∴ s.p = $ 67.305

So, He will pay $ 67.30

Hence The money which Andre pay for the bike is $ 67.30 . Answer

B ) If the bike is discounted by 20 % , let The selling price = s.p'

So,

Discount % = $\dfrac{m.p - s. p }{m . p}$

or, 20 % = 1 - $\dfrac{s. p' }{m . p}$

or, $\dfrac{20 }{100}$ = 1 - $\dfrac{s. p' }{96.15}$

Or, $\dfrac{s. p' }{96.15}$ = 1 - $\dfrac{20 }{100}$

or, $\dfrac{s. p' }{96.15}$ = $\dfrac{100 - 20 }{100}$

Or, $\dfrac{s. p' }{96.15}$ = $\dfrac{80}{100}$

Or, s. p' = $\dfrac{80}{100}$ × 96.15

∴ s.p' = $ 76.92

So, He will pay $ 76.92

Hence The money which Andre pay for the bike is $ 76.92 . Answer

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