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2 years ago

What the answer to 30-32

Mathematics

1 answer:

UNO [17]2 years ago

5 0

-2 is the answer, because it is the answer to the question you are asking

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Work your brain this evening y'all!! I had $3.00. My Mom gave me $10.00. My Dad Gave me $30.00. My Aunt & Uncle gave me $100

liraira [26]

Answer:

150 i think

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

In the expression 4 to the power of 9 the number 9 i called the? A) base B)multiplier C) product D)exponent

harina [27]

In the expression 4 to the power of 9, the number 9 is called the D. exponent.
Number four here is the base, and the exponent is always shown as a superscript to the right of the base. It shows how many times you are supposed to multiply the base by itself.

3 0

3 years ago

Someone please help me on this math problem!

Galina-37 [17]

Look at the picture.

Therefore we have the equation:

10y - 29 = 7y + 19 add 29 to both sides

10y = 7y + 48 subtract 7y from both sides

3y = 48 divide both sides by 3

y = 16

3x + 7 = 5x - 21 subtract 7 from both sides

3x = 5x = -28 subtract 5x from both sides

-2x = -28 divide both sides by (-2)

x = 14

3 0

3 years ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0

2 years ago

Angle $eab$ is a right angle, and $be = 9$ units. what is the number of square units in the sum of the areas of the two squares

Alla [95]

Let the measure of side AB be x, then, the measue of side AE is given by

$AE=\sqrt{9^2-x^2}$ .

Now, ABCD is a square of size x, thus the area of square ABCD is given by

$Area=x^2$

Also, AEFG is a square of size $\sqrt{9^2-x^2}$ , thus, the area of square AEFG is given by

$Area=\left(\sqrt{9^2-x^2}\right)^2=9^2-x^2=81-x^2$

The sum of the areas of the two squares ABCD and AEFG is given by

$x^2+81-x^2=81$

Therefore, the number of square units in the sum of the areas of the two squares ABCD and AEFG is 81 square units.

8 0

2 years ago