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Solnce55 [7]
2 years ago
5

PLEASE HELP ASAP

Mathematics
1 answer:
zheka24 [161]2 years ago
5 0

Answer:

the second forth and fifth on the graph.

Step-by-step explanation: have a good day!

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Select the point that is a solution to the system if inequalities yx^2-6
labwork [276]

Answer:

The correct answer is A.

A(0,-2)

Step-by-step explanation:

Method 1

You just have to plot each point on the graph.

The one that falls within the solution region is the correct choice.

From the graph, A(0,-2) falls within the solution region.

See graph

Method 2

If you substitute the points into the inequalities, the only point that will satisfy both inequalities simultaneously is A.

The first inequality is

y\:

If we substitute A(0,-2), we get;

-2\:


-2\:


This statement is true.

The second inequality is

y\:>\:x^2-6

If we substitute A(0,-2), we get;

-2\:>\:(0)^2-6

This gives,

-2\:>\:-6

This statement is also true.



8 0
3 years ago
Question 12 (2 points)
elena55 [62]

Answer:

A box plot is drawn with end points at 24 and 49.The box extends from 28 to 44 and a vertical line is drawn inside the box at 34.

Step-by-step explanation:

Ordering the data given :

24,28,32,34,40,44,49

We can calculate the 5 number summary required to give the appropriate boxplot that can be produced :

Minimum = 24

Maximum = 49

Median = 1/2(n+1)th term

n = 7

Median = 1/2(8) = 4th term

Median = 34

Lower quartile, Q1 = 1/4(n+1)th term

n = 7

1/4(8) = 2nd term

Q1 = 28

Upper quartile : 3/4(n+1)th term

n = 7

Q3 = 3/4(8) = 6th term

Q3= 44

3 0
3 years ago
A worker is being raised in a bucket lift at a constant speed of 3 ft/s. When the worker's arms are 10 ft off the ground, her co
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H=3t+10 and h=-16t+15t+6

They will never be at the same height at the same time
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3 years ago
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Can you provide more information? Where would the fire be? What type of fire?(wildfire, controlled fire) What is the purpose of the fire?
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3 years ago
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6.find zeroes by factorisation<br><br>4x2 + 5√2 x - 3​
dangina [55]

-13.213203440000000000000

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4 years ago
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