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astra-53 [7]
3 years ago
10

What occurs when ice melts?   A. a chemical change   B. a physical change   C. a nuclear change   D. An atomic compound is newly

formed.
Mathematics
2 answers:
olasank [31]3 years ago
6 0
B. a physical change
kupik [55]3 years ago
3 0
I think it's b , but I'm not sure though
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Ken said that he is going to reduce the number of calories that he eats during the day. Ken's trainer asked him to start off sma
abruzzese [7]
2.200 or 2,200????????????
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3 years ago
What is the simplified form of each expression?<br><br> 7x^–8 × 6x^3
klio [65]
7*6*x^-8*x^3     
42x^-8+3                    (bases same powers add)
42x^-5
1/42x^5
<span>so the simplified </span>form<span> of 7x^-8*6x^3 is=1/42x^5</span>
7 0
3 years ago
Follow the steps to finish solving the equation -3x+18=7x
Svet_ta [14]

Answer:

x = 1.8

Step-by-step explanation:

We have the equation -3x + 18 = 7x. First we do your step 1, and get: 18 = 10x. When doing your step 2, we divide both sides by 10 to isolate x alone. 18/10 = 1.8. X = 1.8

6 0
3 years ago
4a (8a- 4a + 1)<br> Helpehelpeekendnhdhdjdjdjjdfjjfjfjf
Triss [41]
Complete the math in the brackets (4a + 1)

Multiple each term in the brackets by 4a

4a (8a - 4a + 1)
4a (4a + 1)
16a^2 + 4a
6 0
3 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
2 years ago
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