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Dafna1 [17]
3 years ago
5

The CPU of a personal computer has a lifetime that is exponentially distributed with a mean lifetime of six years. a) What is th

e probability that the CPU fails within three years?
Mathematics
1 answer:
amm18123 years ago
7 0

Answer: Our required probability is 0.39.

Step-by-step explanation:

Since we have given that

X be the exponentially distributed with mean life = 6 years

So, E[x]=6

\dfrac{1}{\lambda}=6\\\\\lambda=\dfrac{1}{6}

So, our cumulative distribution function would be

F(x)=1-e^{-\lambda x}

We need to find the probability that the CPU fails within 3 years.

P(X

Hence, our required probability is 0.39.

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Triss [41]
<span>Express log(2)64-log(2)4 as a single logarithm.
Simplify as possible.
Solution: 

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= log(2)[16]
= 4
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3 years ago
Write and equation of the line below ​
blondinia [14]

Answer:

y = 1/4x + 0 or just y = 1/4x

Step-by-step explanation:

First I need the slope so I look at the dots and see how much boxes it goes up and then to the side. So it’s up 2 to the side 8. The slope would be 2/8 but you can simply it by 2 and you get 1/4. And the y intercept is given its zero.

4 0
3 years ago
Evaluate the following
IRINA_888 [86]

(a) [\frac{9}{2.6}  - \frac{2.5^{2} }{2.5} ]^{2}

Answer:

[\frac{9}{2.6}  - \frac{2.5^{2} }{2.5} ]^{2}

= [\frac{9}{2.6}  - \frac{2.5*2.5 }{2.5} ]^{2}

= [\frac{9}{2.6}  - \frac{2.5}{1} ]^{2}

*canceling 2.5 in numerator and denominator*

= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) [[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}    ] ^{2}

Answer:

[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\

*using [x^{a}]^b = x^{ab}*

= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}        

*Again, using [x^{a}]^b = x^{ab}*

= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} }  \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1

Property used: 'Power of a power'

We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

3 0
3 years ago
What am I supposed to do?
aleksley [76]
You take the amount paid and divide it by the amount of cheese. So 10.50 divided by 2.5 equals 4.2 and 12.60 divided by 3 equals 4.2 meaning that one pound of cheese costs $4.20
6 0
3 years ago
T-shirts cost $11 each. Raphael graphs the relationships that give the cost y in dollars of buying x T-shirts. Which ordered pai
nikitadnepr [17]
The answer is B(2,22).
Since 1 shirt costs 11 dollars, 2 shirts will cost 22 dollars. Hope this helps!
7 0
3 years ago
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