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Rainbow [258]
3 years ago
12

Find the slope of the line passing through the points (-8, 9) and (6, 9).

Mathematics
2 answers:
mario62 [17]3 years ago
6 0

Answer:

it is 0

Step-by-step explanation:

rise/run

9-9 / 6 - (-8)

0/14

0

OverLord2011 [107]3 years ago
5 0

Hello there!

Use the slope formula:

m=\frac{y2-y1}{x2-x1}

Now, plug in all the values:

\frac{9-9}{6-(-8)} \\\frac{0}{6+8} \\0

The slope is 0. Why?

If we are given 2 points and their y-coordinates are the same, then the line is a horizontal line. Its rise is zero.

Another formula for Slope is Rise/Run. If the rise (the amount of units we move up) is 0, then the slope is 0.

<h2>Therefore, the slope is 0.</h2>

Hope this helps you!

~Just a felicitous girlie

#HaveAnAmazingDay

SilentNature\\(GraceRosalia)

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Answer:

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Step-by-step explanation:

x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad  x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}

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