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Mariulka [41]
3 years ago
7

You are dealt 13 cards from a shuffled deck of 52 cards. Compute the probability that (a) your hand lacks at least one suit, (b)

you get the both Ace and King of at least one suit, (c) you get all four cards of at least one denomination (all Aces, or all Kings, or all Queens, . . . , or all Twos).

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0

Answer:

Attached is the image of the solution . cheers

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gladu [14]

For this case we have the following expression:

\frac {3} {4} g = \frac {5} {8}

We clear the value of the variable "g", for this:

We multiply by 4 on both sides of the equation:

4 * \frac {3} {4} g = \frac {5} {8} * 4\\3g = \frac {20} {8}

We divide by 3 on both sides of the equation:

\frac {3g} {3} = \frac {20} {8 * 3}\\g = \frac {20} {24}

We simplify:

g = \frac {10} {12} = \frac {5} {6}

Answer:

g = \frac {5} {6}

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1. Given the triangle below, answer the following questions
bogdanovich [222]

Answer:

x=81

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Step-by-step explanation:

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