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allochka39001 [22]
2 years ago
13

Please help i hate algebra this is so confusing 30 pts

Mathematics
2 answers:
jekas [21]2 years ago
7 0
Yeah that’s correct ...........///
Tom [10]2 years ago
3 0

you got it correct.............................

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2. Find the value of the expression 21 – 2a if a = 3.
timama [110]

Answer:

A

Step-by-step explanation:

we just substitute the value of "a" given in the above expression we get

21-2(3)

21-6=15

7 0
3 years ago
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What is the value of w?<br> A.52.5 <br> B.75<br> C.40 <br> D.100
malfutka [58]
The answer is B. 75 because 105 plus 75 equals 180 degrees...... I used to work on this when I was in 6th grade so it is easy to me hope that helped i tried my best hope you get a 100 hundred as your grade

The answer is = B. 75 
5 0
2 years ago
What 2 numbers multiply to -216 and add up to 6
Lena [83]
-12 and 18

hope this helps :)
7 0
2 years ago
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Would appreciate some help with this:<br><br> Verify (sinq+cosq)^2 - 1 = sin2q
Phantasy [73]

Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

(sinq + cosq)^2 =                                     => (a +b)^2 = a^2 + 2ab + b^2

(sinq)^2 + (cosq)^2 + 2 sinq* cosq        => as (sinx)^2 + (cosx)^2 = 1

1 + 2 sinq*cosq              (*)


Setting a = b = q in the trig identity:

sin(a+b) = sina*cosb + cosa*sinb                      

sin(2q) =                      (**)

sinq*cosq + cosq*sinq      => as both terms are identical

2 sinq*cosq


Combining (*) and (**)

(sinq + cosq)^2 = 1 + 2sinq*cosq     => (**) 2sinq*cosq =  sqin(2q)

                          = 1 +  sin(2q)

Hence

(sinq + cosq)^2  = 1 +  sin(2q)            => subtracting 1 from both sides

(sinq + cosq)^2  - 1 =   sin(2q)  

The last statement is what we are trying to prove.



Thank you,

MrB

7 0
3 years ago
Find the missing side?
weeeeeb [17]

Answer:

Hey there!

Pythagorean Theorem: a^2+b^2=c^2

16+25=c^2

41=c^2

c=6.4

Let me know if this helps :)

6 0
3 years ago
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