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3 years ago

Simplify the radical below. sqrt(x^13)

Mathematics

1 answer:

raketka [301]3 years ago

5 0

Answer:

Step-by-step explanation:

√(x^13)= √(x^12)×√x =x^6×√x

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The first term in this arithmetic sequence is 2. The next term is 5 and the pattern continues by adding three to get each of the

Marat540 [252]

Answer:

I don't know how many terms you need so...

2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41, 44, 47, 50, 53, 56, 59, 62, 65, 68, 71, 74, 77, 80, 83, 86, 89, 92, 95, 98, 101, 104, 107, 110

These are the next 35 terms past 5. Hope this answers whatever question you had

6 0

3 years ago

Malika decides to use some of her savings to buy a bicycle. She compares the prices of 3 brands of bicycles: the RacerZ, the Spe

jeka94

So times $64.80 by 2.5. You minus 20 from that, so that the RacerZ is $142. You take that $142 and times that by 1.09. You get 154.78. Therefore;

Speedmonster- 64.80
RacerZ- 142
Swiftee-154.78

Hope this helps. :)

3 0

3 years ago

The length of the base of a square pyramid is 15 inches. The slant height is 10 inches. What is the surface area of the pyramid?

Dimas [21]

Answer: 150

Step-by-step explanation:

15x10= 150

6 0

3 years ago

Ten pounds of mixed birdseed sells for 8.24 per pound. The mixture is obtained from two kinds of birdseed, with one variety pric

Kipish [7]

Answer:

2 pounds of 1st kind and 8 pounds of 2nd kind are mixed.

Explanation:

Given:

Ten pounds of mixed birdseed sells for 8.24 per pound.

Price of the 1st variety of birdseed=5.68 per pound

Price of the 2nd variety of the birdseed=8.88 per pound.

To find :

Pounds of 1st variety of birdseed are used in the mixture=?

Pounds of 2ndvariety of birdseed are used in the mixture=?

Solution:

Let the weight of 1st kind added in mixture be n pounds.

Then weight of 2nd kind will be 10 – n pounds.

Now, total cost of mixture = cost of 1st kind birdseed + cost of 2nd kind birdseed

Weight of mixture x cost per pound = weight of 1st kind x cost per pound + weight of 2nd kind x cost per pound.

Substituting the values,

$10\times8.24 = n\times5.68 + (10-n)\times8.88$

82.4 = 5.68n + 88.8 – 8.88n

8.88n – 5.68n = 88.8 – 82.4

3.2n = 6.4

$n = \frac{3.2}{6.4}$

n = 2

Then, weight of 2nd kind is 10 – 2 = 8 pounds.

Hence, 2 pounds of 1st kind and 8 pounds of 2nd kind are mixed.

5 0

3 years ago

Help me plz cant work it out

svetoff [14.1K]

Answer: 27.80

Step-by-step explanation:

(3/5) x 14 = 8.4

That's 4 of the 2 kilogram tubs and 1 of the 1 kilogram tub (gives 9 kilograms)

4 x 6.15 = 24.60

1 x 3.20 = 3.20

24.60 + 3.20 = 27.80

7 0

4 years ago