Answer:y=
Acosx+Bsinx +cosx ln(cosx)+x sinx
Step-by-step explanation:
given equation y''+y=secx
auxiliary equation

so CF is y=Acosx+Bsinx
now

using wronskian formula

=
now f(x)=secx




now particular integrals are
PI=cosx ln(cosx)+x sinx
total solution
y= C.F+P.I
y=Acosx+Bsinx +cosx ln(cosx)+x sinx
Well he started off right by solving for y=y to find the abscissa of the intersection points between the two points,but then he assumed that their ordinate (y coordinates) are both zero,which is incorrect obviously. To find their ordinate,all we have to do is plug the x values into any of the two equations, since they both will pass through that point ੴ


I chose to plug the values in the second linear equation, since it's easier to compute
<h2>
Points:</h2>
<h2>
( 3 , 13 ) ( -2 , -7 )</h2>
we know that
The sum of exterior angles of any polygon is
degrees
so

therefore
<u>the answer is</u>
the value of x is 
Step-by-step explanation:
Linear pairs = 180°!!!!!
- 1st angle is 2[x]-39 2nd angle is just x
- soooo add the x. 3x-39=180
- 3x=141 x=47
X is just the second angle!!!!!
lol. i toonk geo last year and i cant believe i still remember all this hopefully i got it right!
Answer:
f average = 1
smaller value c = 3
larger value c = 5
Step-by-step explanation: