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zavuch27 [327]
3 years ago
14

Can anyone explain how to do this???

Mathematics
1 answer:
Gwar [14]3 years ago
3 0

Answer:

(x−1)(x−2)(−3x+1)

=((x−1)(x−2))(−3x+1)

=((x−1)(x−2))(−3x)+((x−1)(x−2))(1)

=−3x3+9x2−6x+x2−3x+2

=−3x3+10x2−9x+2

Step-by-step explanation:

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FIND PR.PLS HELP BRAINLIEST...
slega [8]

Answer:

6.2 units.

Step-by-step explanation:

We are given two angles and an opposite corresponding side. To solve for an unknown side, we can use the law of sines.

\frac{8}{sin(90)}=\frac{x}{sin(180-39-90)}=\frac{x}{sin(51)}

Cross multiplying and solving will get you this:

x=\frac{8(sin(51))}{sin(90}

Which can simplify to:

x=8(sin(51))

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x=6.2

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Answer:

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Step-by-step explanation:

13.79-x

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13.79-2.54

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3 years ago
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What is the value of -44.4-7?
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Step-by-step explanation:

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Solve for y: 3(2y + 4) = 4(2y – 1/2).<br> The solution is y =
tatyana61 [14]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

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  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

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