Find an equation for the plane that is perpendicular to the line l(t) = (2, 0, 9)t + (3, −1, 1) and passes through (9, −1, 0).
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Answer:
c ≈ 9.1 m
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is
c² = 4.1² + 8.1² = 16.81 + 65.61 = 82.42 ( take square root of both sides )
c = ≈ 9.1 m ( to the nearest tenth )