Find an equation for the plane that is perpendicular to the line l(t) = (2, 0, 9)t + (3, −1, 1) and passes through (9, −1, 0).
1 answer:
The plane will have its normal vector equal to the direction vector of the line (2, 0, 9). Its equation is
2x +9z = (2, 0, 9)•(9, -1, 0)
2x +9z = 18
You might be interested in
8 * 7 * 6 * 5 * 4 * 3 * 2 * 1
8 = 40320
Z= 138/625 or in decimal form it’s 0.2208
Answer:
46
Step-by-step explanation:
I believe the answer is B
Answer:
Step-by-step explanation:
=> 78% makes:
=> 
<u><em>In simplest form:</em></u>
=>
