Answer:
th part of the field is covered in the second sprint.
Step-by-step explanation:
A football player is running the length of a 100 yard long football field.
Let player sprints x yards with the speed = 2 yards per second.
So time taken to cover x yards player will take time = 
seconds
Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = 
= 
seconds
Now total time taken by the player can be represented by the equation
Now we can solve this equation for the value of x.
x + 100 = 40×4
x + 100 = 160
x = 160 - 100 = 60 yards
And length of the second part will be = 100 - 60 = 40 yards
Now the fraction of the field covered by the player in second sprint will be
= 
= or 40%
Therefore, th part of the field was covered in second sprint.
X²(x - 4) +4 (x - 4)
(x² + 4) (x - 4)
First find the common terms that can enter into both x³ and 4x² then write its down in this case it’s x² that can enter x³ leaving only x _since x³/x² = subtract of the indices. x² will also enter 4x² leaving only four hence you having x² (x - 4)
then do the same for the next pair of terms giving you 4 that can enter into both 4 and 16
Leaving you with +4 (x - 4)
Now you can put the common terms together like so (x² + 4) and choose get one of the other two which are the same= (x - 4)
= (x² + 4) (x - 4)
Answer:
I think C the fourth graph
Step-by-step explanation:
Answer:
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Step-by-step explanation:
dont ask skool questions man
3x² + 2x - 4 = 0
Δ = b² - 4.a.c
Δ = 2² - 4 . 3 . -4
Δ = 4 - 4. 3 . -4
Δ = 52
x = (-b +- √Δ)/2a
x' = (-2 + √52)/2.3
x'' = (-2 - √52)/2.3
x' = 0,8685170918213297
x'' = -1,5351837584879966
2 Decimal places
x' = 0,87
x'' = -1,54
