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sattari [20]
2 years ago
10

What is the slope of the line?

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
8 0
Answer: -5/2

Explanation: Rise over Run. Since the line is going downwards, the slope is negative
You might be interested in
2x^4–5x^3+x^2+3x+2=?<br><br> X=5
DanielleElmas [232]

Answer:

2x^4–5x^3+x^2+3x+2=

2 \times 5^4–5 \times 5^3+5^2+3 \times 5+2

= 2 × 625 – 5 × 125 + 25 + 3 × 5 + 2

=1250 – 625 + 25 + 15 +2

= 1292 – 625

= 667

3 0
2 years ago
Waffle House cookes 8 eggs for every 3 people how many people will 128 eggs feed?
meriva
336 is the amount of eggs that will be cooked
4 0
3 years ago
Read 2 more answers
How to solve 2x+5 if x equals 7
tatuchka [14]

Answer:

2(7) + 5 = 19

Step-by-step explanation:

Okay, so do it like this:

2x+5

x = 7

2(7) + 5

2(7) = 2 x 7

2 x 7 = 14

Now it's 14 + 5

14 + 5 = 19

Your answer is 2(7) + 5 = 19

6 0
2 years ago
What is the interquartile range of this data?
harkovskaia [24]
The interquartile range is 24...
7 0
3 years ago
A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 33.9 wee
MArishka [77]

Answer:

P(35.3 < M < 35.4) = 0.0040.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 33.9, \sigma = 6.7, n = 119, s = \frac{6.7}{\sqrt{119}} = 0.6142

Find the probability that a single randomly selected value is between 35.3 and 35.4

This is the pvalue of Z when X = 35.4 subtracted by the pvalue of Z when X = 35.3. So

X = 35.4

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{35.4 - 33.9}{0.6142}

Z = 2.44

Z = 2.44 has a pvalue of 0.9927

X = 35.3

Z = \frac{X - \mu}{s}

Z = \frac{35.3 - 33.9}{0.6142}

Z = 2.28

Z = 2.28 has a pvalue of 0.9887

0.9927 - 0.9887 = 0.0040

So the answer is:

P(35.3 < M < 35.4) = 0.0040.

4 0
3 years ago
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