The smallest of the three consecutive integers is 24.
<h3>How to solve algebraic word problems?</h3>
Let the 3 consecutive integers be;
x, y and z
Thus;
y = x + 1
z = x + 2
Now, we are told that their sum is equal to 4 times the largest number minus 29. Thus;
x + x + 1 + x + 2 = 4(x + 2) - 29
3x + 3 = 4x + 8 - 29
4x - 3x = 3 + 21
x = 24
Thus, we can conclude that the smallest of the three consecutive integers is 24.
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Answer:
Step-by-step explanation:
Given
Required
Find x
and x are on a straight line.
So:
Make x the subject
Substitute known value
A. Cost=7(Number of People)+35 or y=7x+35
b. 11x<7x+35
c. Subtract 7x from both sides: 4x<35
d. Divide both sides by 4: x< 8.75 people. This means that if the number of lunches ordered is 8 or less, Larry's Lunches will be cheaper. However, if the number of lunches ordered is 9 or more, Donna's Deli will be cheaper. Thus, for an order of 10 lunches, Donna's Deli would charge less.
1 1/5 - 1/3
6/5-1/3
18/15-5/15
13/15 is your answer.
Answer:
6. = A.
5. = B.
4. = C.
Step-by-step explanation:
