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3 years ago

13

PLEASE HELP I've tried everything 30 points!

1 answer:

Luda [366]3 years ago

7 0

Answer:

(x+2)1x-8)=0

x=-2 or x=8

Step-by-step explanation:

The given quadratic expression is

$2 {x}^{2} - 12x - 32$

We equate this expression to zero to get:

$2 {x}^{2} - 12x - 32 = 0$

Let us divide through by 2 to get:

${x}^{2} - 6x - 16 = 0$

Split the middle term to get:

${x}^{2} - 8x + 2x - 16 = 0$

Factor

${x}(x - 8) + 2(x - 8) = 0$

Factor further to get

$(x - 8)(x + 2) = 0$

The solution are

$x = - 2 \: and \: x = 8$

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(X^3+1)dividend (x-1)

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$x^3=x\cdot x^2$ and $x^2(x-1)=x^3-x^2$ . So we have a remainder of

$(x^3+1)-(x^3-x^2)=x^2+1$

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$x=x\cdot1$ and $1(x-1)=x-1$ . Subtracting this from the previous remainder gives a new one of

$(x+1)-(x-1)=2$

and we're done since 2 does not divide $x$ . So we have

$\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}$

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