PLEASE HELP I've tried everything 30 points!

Mathematics

1 answer:

Luda [366]2 years ago

7 0

Answer:

(x+2)1x-8)=0

x=-2 or x=8

Step-by-step explanation:

The given quadratic expression is

$2 {x}^{2} - 12x - 32$

We equate this expression to zero to get:

$2 {x}^{2} - 12x - 32 = 0$

Let us divide through by 2 to get:

${x}^{2} - 6x - 16 = 0$

Split the middle term to get:

${x}^{2} - 8x + 2x - 16 = 0$

Factor

${x}(x - 8) + 2(x - 8) = 0$

Factor further to get

$(x - 8)(x + 2) = 0$

The solution are

$x = - 2 \: and \: x = 8$

You might be interested in

45(15x+20)−7x=56(12x−24)+6 Enter your answer in the box.

zzz [600]

X=1119/2 hope this helps :)

3 0

2 years ago

Find all relative extrema of the function. use the second derivative test where applicable. (if an answer does not exist, enter

Alinara [238K]

The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4

The one relative extreme is a minimum at (-1.5, -3.25).

_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.