7 (6) + 14!!! And this needs to be 20 characters long so I’m adding this
Answer:
a) 658008 samples
b) 274050 samples
c) 515502 samples
Step-by-step explanation:
a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.
So, the number of samples = ⁴⁰C₅ = 658008 samples
b) How many samples of 5 contain exactly one nonconforming chip?
There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways
¹⁰C₁ = 10 ways
then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways
³⁰C₄ = 27405 ways
So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples
c) How many samples of 5 contain at least one nonconforming chip?
The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)
Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples
Total number of samples = 658008
The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples
Micah is 5 inches shorter than twice the height of Jasmine
Micah = 5 inches shorter than 2 x Jasmine
Micah = 2 x Jasmine - 5 <em>(jasmine is 32 inches tall. Replace jasmine with 32)
</em>
Micah = 2 x 32 - 5
Micah = 64 - 5
Micah = 59
Micah is 59 inches tall
4n+7−(7n−8)
=4n+7+−1(7n−8)
=4n+7+−1(7n)+(−1)(−8)
=4n+7+−7n+8
Combine Like Terms
=4n+7+−7n+8
=(4n+−7n)+(7+8)
=−3n+15
Answer:
Step-by-step explanation:
the base of the vase will be where the vase touches the x-axis, that is 10 cm, therefore, the base is 10 cm from the wall
:
b) 25 = x^2 -20x +100, we solve for x to find the closest distance since as we move up the vase the distance to the wall gets closer(assume the y-axis is the wall), then
x^2 -20x +75 = 0 (x-15) * (x-5) = 0
x = 15 and x = 5
we reject x = 15
the shortest distance from the top of the vase to the wall is 5 cm
:
c) this is a left shift of the equation y = (x-10)^2
from b) we know that the left shift is 5 cm
10 - 5 = 5 cm from the wall to the base
:
d) y = (x-10+5)^2
y = (x-5)^2
