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3 years ago

What is the solution of the system of equations? y= -2x+8 y= x-4

Mathematics

2 answers:

Taya2010 [7]3 years ago

7 0

X=4, y=0 my answer is too short but I'm to lazy to type the whole pr0cess

Alinara [238K]3 years ago

4 0

We can solve by substituting x-4 for y in the first equation.
x-4 = -2x+8
3x = 12
x = 4

Then plug in 4 for x in one of the equations.
y = 4-4
y = 0
OR
y = -2(4)+8
y = -8+8
y = 0

So the solution is (4,0)

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A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. The rang

VARVARA [1.3K]

Answer:

$\theta=24.4^\circ$

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

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3 years ago

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netineya [11]

3^8 = 6561
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NemiM [27]

$\frac{1}{6}$ or 0.167 pounds more butter was used than sugar

Solution:

Given that, Desmond's Desserts made a batch of fresh scones with 2/3 of a pound of butter and 1/2 of a pound of sugar

To find: Amount of butter used than sugar

From given information,

$\text{Butter used} = \frac{2}{3} \text{ pound }$

$\text{Sugar used } = \frac{1}{2} \text{ pound }$

To find how much butter is used than sugar, find the difference between them

$Difference = Butter\ used - Sugar\ used$

$Difference = \frac{2}{3} - \frac{1}{2}\\\\Difference = \frac{2 \times 2-1 \times 3}{3 \times 2}\\\\Difference =\frac{4-3}{6}\\\\Difference =\frac{1}{6} = 0.167\\\\$

Thus $\frac{1}{6}$ or 0.167 pounds more butter was used than sugar

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