The minimum production cost of company 2 is greater than the minimum production cost of company 1. We arrived at this value by comparing the production cost of both companies.
<h3>What is meant by minimum production cost?</h3>
The overall cost incurred by a company to manufacture a product or provide services is known as the cost of production.
The objective of every company is to keep this cost at minimum, hence the minimum production cost.
<h3>How do find minimum Production Cost?</h3>
Recall that the production function is given as:
f(x) = 0.25x² - 8x + 600
Inserting the values given by the schedule we have
- f(6) = 0.25(6²) - 8(6) + 600 = 561
- f(8) = 0.25(8²) - 8(8) + 600 = 552
- f(10) = 0.25(10²) - 8(10) + 600 = 545
- f(12) = 0.25(12²) - 8(12) + 600 = 540
- f(14) = 0.25(14²) - 8(14) + 600 = 537
For company 2, we are given the various production costs as;
x - g(x)
6 - 862.2
8 - 856.8
10 - 855
12 - 856.8
14 - 862.2
Juxtaposing the above, we can infer that the minimum production cost of company 2 is greater than the minimum production cost of company 1.
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The calculated pH of the solutions are given below:
- The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
- The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
- The pH of the solution after 20.0 ml of base is added to it is calculated as 7.
<h3>What is pH?</h3>
This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.
HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.
Mol of HBr = Mol * Vol
= 0.200 * 20mL
= 4 mmol
A. Moles of NaOH added
= 0.2 X 14
= 2.8 mmol
Moles of H+ that did not react
= 4 - 2.8
= 1.2 mmol
1.2/1000 = 0.0012 moles
Total volume = 20 + 14
= 34 mL to litres
= 0.034 L
Molarity of H+ = 0.0012 / 0.034L
= 0.035 M
-log[0.035] = 1.45
The pH of the solution is 1.45
B. NaOH added = 19.8 * 0.2 =
3.96 mmoles
The unreacted solution
= 4.0 - 3.96
= 0.04 mmol
0.04/1000 = 0.00004 moles
Total volume = 20 + 19.8
= 39.8mL
Converted to litres = 0.0398L
Molarity = 0.00004 / 0.0398L
= 0.001
-log(0.001) = 3.0
The ph Is therefore 3.0
C. Moles of NaOH added = 0.2*20mL = 4mmol
All the H+ are going to be consumed here. This would result into a neutral solution pH = 7
<u>Complete question:</u>
20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.
A. 14.0 mL
B. 19.8 mL
C. 20.0 mL
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The true statement about the graph of f(x) is 
The graph of f(x) is a straight line that passes through the points (-5,0) and (0,3).
Start by calculating the slope (m)
So, we have:
Simplify
The equation of the line is then calculated as:
This gives
Open bracket
Express y as a function of x
Hence, the true statement about the graph of f(x) is
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I think it is true
if me gets it wrong me sorry me not
that smart ༎ຶ‿༎ຶ
