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miss Akunina [59]
3 years ago
12

Find the number of real number solutions for the equation. x2 − 18 = 0

Mathematics
1 answer:
choli [55]3 years ago
5 0
Add 18 on both sides of the equation
18+0 = 18
18÷2 = 9
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Find a vector equation and parametric equations for the line through the point (7,4, 5) and parallel to the vector 3i 2j-k .
aleksley [76]

Answer: vector equation r = (7+3t)i + (4+2t)j + (5 - 5t)k

parametric equations: x = 7 + 3t; y = 4 + 2t; z = 5 - 5t

Step-by-step explanation: The vector equation is a line of the form:

r = r_{0} + t.v

where

r_{0} is the position vector;

v is the vector;

For point (7,4,5):

r_{0} = 7i + 4j + 5k

Then, the equation is:

r = 7i + 4j + 5k + t(3i + 2j - k)

<u><em>r = (7 + 3t)</em></u><u><em>i</em></u><u><em> + (4 + 2t)</em></u><u><em>j </em></u><u><em>+ (5 - 5t)</em></u><u><em>k</em></u>

The parametric equations of the line are of the form:

x = x_{0} + at

y = y_{0} + bt

z = z_{0} + ct

So, the parametric equations are:

<em><u>x = 7 + 3t</u></em>

<em><u>y = 4 + 2t</u></em>

<em><u>z = 5 - 5t</u></em>

4 0
3 years ago
Battery packs in electric go-carts need to last a fairly long time. The run-times (time until it needs to be recharged) of the b
pav-90 [236]

Answer:

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2, \sigma = 0.33

What is the minimum level for which the battery pack will be classified as highly sought-after class

At least the 100-10 = 90th percentile, which is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 2}{0.33}

X - 2 = 0.33*1.28

X = 2.42

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

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3 years ago
Solve for d. 8/12 = 62/d
mamaluj [8]

Answer: d = 93

Step-by-step explanation: coz I juss know

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i think it would be d.) 2 cents

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