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hram777 [196]
3 years ago
12

Find a vector equation and parametric equations for the line through the point (7,4, 5) and parallel to the vector 3i 2j-k .

Mathematics
1 answer:
aleksley [76]3 years ago
4 0

Answer: vector equation r = (7+3t)i + (4+2t)j + (5 - 5t)k

parametric equations: x = 7 + 3t; y = 4 + 2t; z = 5 - 5t

Step-by-step explanation: The vector equation is a line of the form:

r = r_{0} + t.v

where

r_{0} is the position vector;

v is the vector;

For point (7,4,5):

r_{0} = 7i + 4j + 5k

Then, the equation is:

r = 7i + 4j + 5k + t(3i + 2j - k)

<u><em>r = (7 + 3t)</em></u><u><em>i</em></u><u><em> + (4 + 2t)</em></u><u><em>j </em></u><u><em>+ (5 - 5t)</em></u><u><em>k</em></u>

The parametric equations of the line are of the form:

x = x_{0} + at

y = y_{0} + bt

z = z_{0} + ct

So, the parametric equations are:

<em><u>x = 7 + 3t</u></em>

<em><u>y = 4 + 2t</u></em>

<em><u>z = 5 - 5t</u></em>

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